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GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
im posting it
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow 2} x^38 \div x^26x+8\]
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
x tends to 2
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
it did not specify it just says find the limit
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
if you replace x by 2 and get \(\frac{0}{0}\) then factor and cancel
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 i know but thats not the answer i think i would have to factorize the denominator
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
@matt1888 how do i factor the numerator
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
\[ \lim_{x \rightarrow 2} \frac{x^3  8}{x^2  6x + 8} = \lim_{x \rightarrow 2} \frac{(x  2)(x^2 + 2x + 4)}{(x2)(x4)}\] Cancel out \( (x 2) \) on both numerator and denominator and put the values of x to get your limit.
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
and if you do get \[\frac{0}{0}\] when replacing x by 2 you know how it factors, it must be \[\frac{(x2)(\text{something})}{(x2)(\text{something else})}\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
don't forget, if you know a zero of a polynomial you know how it factors
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
thanks @satellite73 @experimentX and @matt1888 :)
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
in other words it is not a miracle that both numerator and denominator have a common factor of \((x2)\) they must have a common factor
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
also don't forget (because you will see it again) that \[a^3b^3=(ab)(a^2+ab+b^2)\]
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
yes i do and i have more questions coming up because i'm preparing for Final exams so i really would appreciate the help from you all :)
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 whenever i see a equation like that in the numerator i keep forgetting that rule
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
don't forget for the test! also know that \(a^3+b^3=(a+b)(a^2ab+b^2)\)
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
@matt1888 im gonna write them down until i know it and btw how was your test?
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
if i could i would have given you all a medal :D
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
not to be picky @matt1888 (and byw congratulation on finishing your final) but you cannot "foil it out" because a) it is three terms by two terms and b) you are factoring, not multiplying, so unless you know the answer you will probably not be able to get it (although you could divide is suppose)
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
@matt1888 thats awesome i want to aim high in my finals and go in there with confidence but i have some real issues doing graphs, deferentiation and integration and so forth
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
@matt1888 i will let you know when i look back on the topics these are just past paper questions im going through now
 2 years ago

GoldRush18 Group TitleBest ResponseYou've already chosen the best response.0
Calculus at Pre University
 2 years ago
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