Abbie23
From a hot air balloon, the angle between a radio antenna straight below and the base of the library downtown is 57°, as shown below. If the height of the balloon is 15 miles, what is the distance between the radio antenna and the library?
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SmoothMath
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Howdy.
SmoothMath
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|dw:1336435993255:dw|
Is this right?
SmoothMath
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What is wrong?
Abbie23
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|dw:1336436127388:dw|
SmoothMath
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Oooh. Cool. Got it.
SmoothMath
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Alright, so the first step is to figure out which trig function is worth using. To figure this out, I like to find where the angle I know is and then label my sides opposite, adjacent, and hypotenuse.
SmoothMath
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You know which side is which?
Abbie23
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The hypotenuse is the opposite side of 15 miles and the adjacent side is...have no idea?
SmoothMath
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|dw:1336436548036:dw|
SmoothMath
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Cool? The 15 miles side is adjacent to the angle we know. The x side is opposite from that angle. The hypotenuse is always the long side, the one opposite from the right angle.
Abbie23
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Well I got the hypotenuse side right :)
Okay got the other sides, thanks!
DoomDude
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1 sec...
DoomDude
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I am not really sure, I am not good at geometry, would you like me to try to get someone else here?
DoomDude
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sorry, but do you want me to try to get someone that know it here?
Abbie23
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It's okay :)
You don't have to do that! Haha I'll just guess :)
DoomDude
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no! wait, let me get someone
DoomDude
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@amistre64 @lgbasallote @imranmeah91 @LagrangeSon678 @AccessDenied
SmoothMath
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Mildly obnoxious, bro. lols.
DoomDude
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it works...
SmoothMath
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Abbie, the side you know is adjacent. The side you need to know is opposite. See that?
Which trig function involves opposite and adjacent?
Abbie23
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Oh okay I see that. And tangent!
lgbasallote
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uhmm im assuming no help necessary anymore?
DoomDude
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I am pretty sure that it is... Is it abbie?
SmoothMath
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Yes, it's tangent. Write an equation using tangent.
Tan(57) = opposite/adjacent = x/15
solve for x
Abbie23
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Yeah, I think so too @Drake
Thank you for helping me :)
Abbie23
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Thanks @SmoothMath :)