Here's the question you clicked on:
nickymarden
derive the equation.
Senx? What kind of math is this? :o
Is that supposed to be sin x?
sorry, it's in portugese :) and yes it is.
Probably. But what is the question asking for? Derive it from...?
Okay, so \(g(x)=(\sin x+\sqrt{x})^3\cdot\sqrt{x^4+2}\) and you're looking for \(g'(x)\)?
no wonder i have seen these sen x for a lot of times i thought they taught secret trigonometry to people -___-
So, use the product rule and the chain rule, yeah? Which part are you getting stuck at?
i'm sorry for taking long. I was tryig to do it by myself. I just can't do it lol
Show us your work so we can see where you're getting lost.
First step, product rule, right? So \(f(x)=(\sin x+\sqrt{x})^3, g(x)=\sqrt{x^4+2}\), and we're finding \(f'(x)g(x)+g'(x)f(x)\)
\[g(x) = (\sin x + \sqrt x)^3 *\sqrt {x^4 +2}\]This gets messy...\[\frac {dg}{dx} = (\sin x + \sqrt x)^3 \frac {d}{dx} \left[ \sqrt {x^4 +2} \right] + \sqrt {x^4 +2} \frac {d}{dx} \left[ (\sin x + \sqrt x)^3 \right]\]
As nbouscal said, where do you get stuck?
yeah, i get lost in all the algebra.
i just erased it all, let me try again lol.
Take it one step at a time. First step is to find f'(x), so derive \((\sin x + \sqrt x)^3\) using the chain rule.
thank you for the help :))