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16 chances on the first pick
15 on the second pick
14, then 13 then 12 ... then its full

but, that counts abc as different from bca

to weed out the repeats since groups dont care about order we can divide that by 5!

16P5
----- = 16C5
5!

and that equals??

you should have material that explains the notation better than I can

ok. then whats the final anseer?

\[\dbinom{16}{5}\] but that doesn't answer the question, it just restates it in notation