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How do you find the sides of a triangle if they only give you 1 side but all 3 degrees of the angles.

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That's a special triangle. In the 30-60-90 triangle, the proportion of the sides are \(\ \sqrt{3}:1:2\), respectively.
How would I solve for the sides though?

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So in this case, that means: |dw:1336450392069:dw|
That means the side lengths are ....?
7, 14, and 12?
Use the Law of Sines
Ummm... Well, you have 7, and 14, so substitute 7 as x in the shortest side, and get 7sqrt3. So the answer is \(\ \huge 7, 14, 7\sqrt{3} \).
I thought that was 7*the sqrt of 3 lol
@robtobey I was going to suggest that at first; however, I think this method is equally as effective.
@ThaJokersRiddles Does this make sense to you now?
The problem statement does not infer a right triangle.
@robtobey, @ThaJokersRiddles drew the problem that indicates a right angle.
Ok. I stand corrected.
However, the law of sines would be effective had this been a non-right triangle.

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