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Romero

  • 3 years ago

what's (e^ix)^2 where x is a variable

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  1. Romero
    • 3 years ago
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    where\[i =\sqrt{-1}\]

  2. vamgadu
    • 3 years ago
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    it is e^i(2x)

  3. Romero
    • 3 years ago
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    If I integrate that from 0 to 2pi what will it be?

  4. Romero
    • 3 years ago
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    in respect to x

  5. vamgadu
    • 3 years ago
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    i is just a constant the integration will be same as that for e^kx

  6. inkyvoyd
    • 3 years ago
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    e^(iPi)=cos x+i sin x

  7. inkyvoyd
    • 3 years ago
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    just treat i as a constant; you will be fine.

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