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RomeroBest ResponseYou've already chosen the best response.1
\[\int\limits_0^{2 pi} (\sqrt{1/(3 pi)}+e^{i x}\sqrt{1/(6 pi)} )^2 dx = 2/3 \]
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
The e^ix is really bugging me.
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[\int\limits_0^{2\pi}\sqrt{\frac{1}{3\pi}}+e^{ix}\sqrt{\frac{1}{{(6\pi)}^2}}\text d x=\frac 2 3\]
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
no no The whole thing inside the integral is squared.
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
That's why I have a parentheses in the beginning it just doesn't show it that well when i used equations.
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[\int\limits_0^{2\pi}\left( {\sqrt{\frac{1}{3\pi}}+e^{ix}\sqrt{\frac{1}{6\pi}}}\right)^2\text d x=\frac 2 3\]
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
So do I just foil it out and find the integral?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
turn e^(ix) into cos x+i sin x.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
If it really bothers you that much. I would just treat i as a constnat. Replace i with g and just integrate it like a constant.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
Then, replace the g's back with i's. Remember that i^2=1
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
If I carry out the foil I know that I can split it into three different integral with the first one being integrating 1/3pi If I do that I can simply take out 1/3pi since it's a constant and I get (1/3pi)(2pi0)=2/3 which is the answer but how does that other part cancel out?
 one year ago

christbotBest ResponseYou've already chosen the best response.1
Can you copy and paste your integral it into Wolfram Alpha? It will show you how to do it stepbystep
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
I would input that into mathematica, but unfortunately my laptop with its installation is being fixed atm
 one year ago

christbotBest ResponseYou've already chosen the best response.1
My calc 2 teacher avoided imaginary numbers. So I'm really curious now.
 one year ago

christbotBest ResponseYou've already chosen the best response.1
Mathematica is on my dead mac... Ugh
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
Oh I think I know what I did wrong. I was suppose to multiply the inside function with it's complex conjugate so it cancels out all imaginar values.
 one year ago

christbotBest ResponseYou've already chosen the best response.1
Anyone have Mac OS X up. Grapher could probably do it.
 one year ago

christbotBest ResponseYou've already chosen the best response.1
Change it to polar form maybe?
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
No the thing is that I was suppose to multiply imaginary function with imaginary and that just cancels out all the imaginaries.
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
what do i enter into grapher? @Christbot
 one year ago

christbotBest ResponseYou've already chosen the best response.1
Wait, wait never about Grapher... Here http://en.wikipedia.org/wiki/Integration_using_Euler%27s_formula
 one year ago

christbotBest ResponseYou've already chosen the best response.1
You guys familiar with Euler's formula?
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
Yes but I don't need to use it at this point.
 one year ago

christbotBest ResponseYou've already chosen the best response.1
Have you tried foiling that giant square and breaking up the integral and placing the e^ix before the integral?
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
That was the original problem I just wrote it wrong.
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
I actually got 1 with the addition of some leftover integrals that should cancel out yet I don't really know why.
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
Ouch indeed I hate my life right now. lol
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
shouldn't post your phone number on the internet lol and I don't have an iphone. :(
 one year ago

christbotBest ResponseYou've already chosen the best response.1
I'm just facebooking myself the input... I'll work to copy and paste, lol
 one year ago

christbotBest ResponseYou've already chosen the best response.1
What the hell?! Wolfram won't integrate it?!
 one year ago

christbotBest ResponseYou've already chosen the best response.1
Can't we let 1 = trig identity? Wow...
 one year ago

christbotBest ResponseYou've already chosen the best response.1
bam I got it as an indefinite integral! Gotta wait for my slow phone, sorry!
 one year ago

christbotBest ResponseYou've already chosen the best response.1
Want the last bit or you got it?
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
*high five* thanks again!! really helped me out!
 one year ago

christbotBest ResponseYou've already chosen the best response.1
No prob! I love a good problem.
 one year ago

christbotBest ResponseYou've already chosen the best response.1
Oh the web version works for free. Yeah, sometime you just gotta tinker with the input. I'm deleting the image links, but here is my mathy blog, FWIW http://mathstem.blogspot.com/ I'll delete my cell# too, lol!
 one year ago
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