## krissywatts Group Title is 2x-5y=10 and -2x=3y+6 infinite or no solution 2 years ago 2 years ago

1. krissywatts Group Title

i got no solution

2. Tnzundu Group Title

Is it a system of equations? If so, simple to solve x = -15/8 and y = -3/4

3. krissywatts Group Title

yup

4. atlas Group Title

y=-2 and x=0 The system has a finite solution

5. atlas Group Title

Add the corresponding left hand and right hand sides of both the equations

6. kcpaas Group Title

I agree with atlas. It has a finite solution (y = -2, x=0). Here's a detailed solution: You have these 2 equations: $Eq 1: 2x - 5y = 10$$Eq 2: -2x = 3y + 6$ Now, subtract 3y to both sides of Eq2 to get: $Eq 1: 2x - 5y = 10$$Eq 2: -2x - 3y = 6$ Add the corresponding sides of the equations: $(2x + (-2x)) + ((-5y) + (-3y)) = 10 + 6$ and you'll get: $-8y = 16 \rightarrow y = -2$ To get x, just substitute -2 to y in one of the equations, say in Eq1: $2x -5(-2) = 10$$2x + 10 = 10$$2x = 0$$x =0$ You'll get the same result even if you do the substitution in Eq2. :)

7. jainarayan Group Title

kcpass ,u have given answer with accurate precision.