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krissywatts Group TitleBest ResponseYou've already chosen the best response.0
i got no solution
 2 years ago

Tnzundu Group TitleBest ResponseYou've already chosen the best response.0
Is it a system of equations? If so, simple to solve x = 15/8 and y = 3/4
 2 years ago

atlas Group TitleBest ResponseYou've already chosen the best response.1
y=2 and x=0 The system has a finite solution
 2 years ago

atlas Group TitleBest ResponseYou've already chosen the best response.1
Add the corresponding left hand and right hand sides of both the equations
 2 years ago

kcpaas Group TitleBest ResponseYou've already chosen the best response.1
I agree with atlas. It has a finite solution (y = 2, x=0). Here's a detailed solution: You have these 2 equations: \[Eq 1: 2x  5y = 10\]\[Eq 2: 2x = 3y + 6\] Now, subtract 3y to both sides of Eq2 to get: \[Eq 1: 2x  5y = 10\]\[Eq 2: 2x  3y = 6\] Add the corresponding sides of the equations: \[(2x + (2x)) + ((5y) + (3y)) = 10 + 6\] and you'll get: \[8y = 16 \rightarrow y = 2\] To get x, just substitute 2 to y in one of the equations, say in Eq1: \[2x 5(2) = 10\]\[2x + 10 = 10\]\[2x = 0\]\[x =0\] You'll get the same result even if you do the substitution in Eq2. :)
 2 years ago

jainarayan Group TitleBest ResponseYou've already chosen the best response.0
kcpass ,u have given answer with accurate precision.
 2 years ago
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