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TnzunduBest ResponseYou've already chosen the best response.0
Is it a system of equations? If so, simple to solve x = 15/8 and y = 3/4
 one year ago

atlasBest ResponseYou've already chosen the best response.1
y=2 and x=0 The system has a finite solution
 one year ago

atlasBest ResponseYou've already chosen the best response.1
Add the corresponding left hand and right hand sides of both the equations
 one year ago

kcpaasBest ResponseYou've already chosen the best response.1
I agree with atlas. It has a finite solution (y = 2, x=0). Here's a detailed solution: You have these 2 equations: \[Eq 1: 2x  5y = 10\]\[Eq 2: 2x = 3y + 6\] Now, subtract 3y to both sides of Eq2 to get: \[Eq 1: 2x  5y = 10\]\[Eq 2: 2x  3y = 6\] Add the corresponding sides of the equations: \[(2x + (2x)) + ((5y) + (3y)) = 10 + 6\] and you'll get: \[8y = 16 \rightarrow y = 2\] To get x, just substitute 2 to y in one of the equations, say in Eq1: \[2x 5(2) = 10\]\[2x + 10 = 10\]\[2x = 0\]\[x =0\] You'll get the same result even if you do the substitution in Eq2. :)
 one year ago

jainarayanBest ResponseYou've already chosen the best response.0
kcpass ,u have given answer with accurate precision.
 one year ago
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