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Yeah can someone show me the steps or what trig identities you used.

\[\frac{\cos^2(x)-\sin^2(x)}{\sin(x)}-2=\sin^2(x)\]

it's not you, latex is not rendering properly.

You know you can edit your question right?

I see the latex just fine

\[\frac{\cos^2(x)-\sin^2(x)}{\sin(x)-2}=\sin^2(x) ?\]

Aha, hard refresh works!

I'm doing eigen values and eigen functions so the left expression has to equal the right.

You said you wrote it wrong? Did I write it right?

-1-2 does not equal 1

no questions?

What do you suggest I do in order to get them equal?

they are not equal