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anonymous
 4 years ago
Show how ((cos^2(x)sin^2(x))/sin(x))2= sin^2(x)
anonymous
 4 years ago
Show how ((cos^2(x)sin^2(x))/sin(x))2= sin^2(x)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah can someone show me the steps or what trig identities you used.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{\cos^2(x)\sin^2(x)}{\sin(x)}2=\sin^2(x)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's not you, latex is not rendering properly.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You know you can edit your question right?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1I see the latex just fine

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{\cos^2(x)\sin^2(x)}{\sin(x)2}=\sin^2(x) ?\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Aha, hard refresh works!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm doing eigen values and eigen functions so the left expression has to equal the right.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1You said you wrote it wrong? Did I write it right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry I deleted the wrong one already. The one I wrote is right. Anyways I should rephrase my questions. I want the left side to equal the right side. How can I change the left side in order to make the equation true so that the left hand side equals the right hand side?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1\sin^2(x)\sin^2(x)}{\sin(x)}2=\frac{12\sin^2(x)}{\sin(x)}2=\frac{12\sin^2(x)2\sin(x)}{\sin(x)}\] hmmm.... I don't think they are the same .... Did you see if you could find a counterexample?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[x=\frac{\pi}{2}\] \[\frac{\cos^2(x)\sin^2(x)}{\sin(x)}2=\sin^2(x)\] \[\frac{\cos^2(\frac{\pi}{2})\sin^2(\frac{\pi}{2})}{\sin(\frac{\pi}{2})}=\frac{01}{1}=1\] But the other side is 1 when x=pi/2 Therefore both sides are not the same

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.112 does not equal 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What do you suggest I do in order to get them equal?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1this is not an identity I gave you a counterexample above try pluggin' in pi/2 for x we do not get the same thing on both sides unless you meant to type something else
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