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Romero Group TitleBest ResponseYou've already chosen the best response.0
Yeah can someone show me the steps or what trig identities you used.
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{\cos^2(x)\sin^2(x)}{\sin(x)}2=\sin^2(x)\]
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.0
it's not you, latex is not rendering properly.
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.0
You know you can edit your question right?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
I see the latex just fine
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{\cos^2(x)\sin^2(x)}{\sin(x)2}=\sin^2(x) ?\]
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.0
Aha, hard refresh works!
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.0
I'm doing eigen values and eigen functions so the left expression has to equal the right.
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You said you wrote it wrong? Did I write it right?
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.0
Sorry I deleted the wrong one already. The one I wrote is right. Anyways I should rephrase my questions. I want the left side to equal the right side. How can I change the left side in order to make the equation true so that the left hand side equals the right hand side?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{1\sin^2(x)\sin^2(x)}{\sin(x)}2=\frac{12\sin^2(x)}{\sin(x)}2=\frac{12\sin^2(x)2\sin(x)}{\sin(x)}\] hmmm.... I don't think they are the same .... Did you see if you could find a counterexample?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[x=\frac{\pi}{2}\] \[\frac{\cos^2(x)\sin^2(x)}{\sin(x)}2=\sin^2(x)\] \[\frac{\cos^2(\frac{\pi}{2})\sin^2(\frac{\pi}{2})}{\sin(\frac{\pi}{2})}=\frac{01}{1}=1\] But the other side is 1 when x=pi/2 Therefore both sides are not the same
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
12 does not equal 1
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
no questions?
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.0
What do you suggest I do in order to get them equal?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
they are not equal
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
this is not an identity I gave you a counterexample above try pluggin' in pi/2 for x we do not get the same thing on both sides unless you meant to type something else
 2 years ago
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