A community for students.
Here's the question you clicked on:
 0 viewing
Romero
 2 years ago
Show how ((cos^2(x)sin^2(x))/sin(x))2= sin^2(x)
Romero
 2 years ago
Show how ((cos^2(x)sin^2(x))/sin(x))2= sin^2(x)

This Question is Closed

Romero
 2 years ago
Best ResponseYou've already chosen the best response.0Yeah can someone show me the steps or what trig identities you used.

Romero
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{\cos^2(x)\sin^2(x)}{\sin(x)}2=\sin^2(x)\]

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0it's not you, latex is not rendering properly.

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0You know you can edit your question right?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1I see the latex just fine

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{\cos^2(x)\sin^2(x)}{\sin(x)2}=\sin^2(x) ?\]

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0Aha, hard refresh works!

Romero
 2 years ago
Best ResponseYou've already chosen the best response.0I'm doing eigen values and eigen functions so the left expression has to equal the right.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1You said you wrote it wrong? Did I write it right?

Romero
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry I deleted the wrong one already. The one I wrote is right. Anyways I should rephrase my questions. I want the left side to equal the right side. How can I change the left side in order to make the equation true so that the left hand side equals the right hand side?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1\sin^2(x)\sin^2(x)}{\sin(x)}2=\frac{12\sin^2(x)}{\sin(x)}2=\frac{12\sin^2(x)2\sin(x)}{\sin(x)}\] hmmm.... I don't think they are the same .... Did you see if you could find a counterexample?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1\[x=\frac{\pi}{2}\] \[\frac{\cos^2(x)\sin^2(x)}{\sin(x)}2=\sin^2(x)\] \[\frac{\cos^2(\frac{\pi}{2})\sin^2(\frac{\pi}{2})}{\sin(\frac{\pi}{2})}=\frac{01}{1}=1\] But the other side is 1 when x=pi/2 Therefore both sides are not the same

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.112 does not equal 1

Romero
 2 years ago
Best ResponseYou've already chosen the best response.0What do you suggest I do in order to get them equal?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1this is not an identity I gave you a counterexample above try pluggin' in pi/2 for x we do not get the same thing on both sides unless you meant to type something else
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.