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anonymous
 4 years ago
Calc 3..Find an xyz equation for the plane that is perpendicular to {2,1,1} and goes through the point {1,1,0}
anonymous
 4 years ago
Calc 3..Find an xyz equation for the plane that is perpendicular to {2,1,1} and goes through the point {1,1,0}

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(2,1,1) is the normal vector? or just a point?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The equation of the plane is 2 x y z = d\\ to find d. The plane has to go through the point (1,1,0} 2(1) (1) 0 =d 2 + 1 =d d=3 The equation of the plane is 2 x y z =3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0seems right except that that would be containing the given vector, as opposed to being orthogonal.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and yes sorry that is the normal vector
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