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Calc 3..Find an xyz equation for the plane that is perpendicular to {2,1,1} and goes through the point {1,1,0}
 one year ago
 one year ago
Calc 3..Find an xyz equation for the plane that is perpendicular to {2,1,1} and goes through the point {1,1,0}
 one year ago
 one year ago

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edr1cBest ResponseYou've already chosen the best response.0
(2,1,1) is the normal vector? or just a point?
 one year ago

eliassaabBest ResponseYou've already chosen the best response.2
The equation of the plane is 2 x y z = d\\ to find d. The plane has to go through the point (1,1,0} 2(1) (1) 0 =d 2 + 1 =d d=3 The equation of the plane is 2 x y z =3
 one year ago

stranger7Best ResponseYou've already chosen the best response.0
seems right except that that would be containing the given vector, as opposed to being orthogonal.
 one year ago

stranger7Best ResponseYou've already chosen the best response.0
and yes sorry that is the normal vector
 one year ago
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