A community for students.
Here's the question you clicked on:
 0 viewing
GoldRush18
 2 years ago
The circle C has equation (x3)^2+(y4)^2=25.
i. State the radius and the coordinates of the centre of C.
ii. Find the equation of the tangent at the point (6,8) on C.
iii. Calculate the coordinates of the points of intersection of C with the straight line y=2x+3.
GoldRush18
 2 years ago
The circle C has equation (x3)^2+(y4)^2=25. i. State the radius and the coordinates of the centre of C. ii. Find the equation of the tangent at the point (6,8) on C. iii. Calculate the coordinates of the points of intersection of C with the straight line y=2x+3.

This Question is Closed

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1where do you have problem??

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1let y=mx+c be equation of your tangent dw:1336583832242:dw

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1find the value of m2 put the all the values m2, (6,8) in y = mx + c ... and find the value of c. then you have tangent!!

GoldRush18
 2 years ago
Best ResponseYou've already chosen the best response.0ok what about part 3

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1\[ (x  3)^2 + ((2x+3)  4)^2 = 25 \] Find the value of x, and put the value of x in equation of circle ... and find corresponding y

GoldRush18
 2 years ago
Best ResponseYou've already chosen the best response.0ok im still on part 2 when it comes to graph and stuff i just cant get it thanks though

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1you know how to find slope ... ?? from two points??

GoldRush18
 2 years ago
Best ResponseYou've already chosen the best response.0is that the same thing as the gradient

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1yes ... \[ m = \frac{y_2  y_1}{x_2  x_1}\]

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1allright you know when two lines are perpendicular, if m1 and m2 be their gradient or slope then \( m_1 * m_2 = 1\) ??

GoldRush18
 2 years ago
Best ResponseYou've already chosen the best response.0no i didnt know that so what are the values i should include for this part

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1m1 is just you calculated ... slope(gradient) of that radius!! m2 .. you have to calculate!! using the relation above.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1http://www.khanacademy.org/math/algebra/linearequationsandinequalitie/v/perpendicularlines?playlist=Algebra+I+Worked+Examples http://www.mathopenref.com/coordperpendicular.html I am not sure if it will help!!

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1No .. you should get m1*m2 = 1 (m1 = 4/3) m2 = 3/4

GoldRush18
 2 years ago
Best ResponseYou've already chosen the best response.0how do i get C which is the y intercept?

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1you know one point ... so it satisfies that equation m = 3/4 (x,y) = (6,8) y = mx+c, c=??

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1Oo .. put the values of x=6 and y=8 since (x,y) is solution and we already know this!!

GoldRush18
 2 years ago
Best ResponseYou've already chosen the best response.0and im stuck once more

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1put y = 2x+3 on (x3)^2+(y4)^2=25 and find the value of x
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.