GoldRush18
  • GoldRush18
The circle C has equation (x-3)^2+(y-4)^2=25. i. State the radius and the coordinates of the centre of C. ii. Find the equation of the tangent at the point (6,8) on C. iii. Calculate the coordinates of the points of intersection of C with the straight line y=2x+3.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
GoldRush18
  • GoldRush18
@experimentX
experimentX
  • experimentX
where do you have problem??
GoldRush18
  • GoldRush18
part 2

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More answers

experimentX
  • experimentX
let y=mx+c be equation of your tangent |dw:1336583832242:dw|
experimentX
  • experimentX
find the value of m2 put the all the values m2, (6,8) in y = mx + c ... and find the value of c. then you have tangent!!
GoldRush18
  • GoldRush18
ok what about part 3
experimentX
  • experimentX
\[ (x - 3)^2 + ((2x+3) - 4)^2 = 25 \] Find the value of x, and put the value of x in equation of circle ... and find corresponding y
GoldRush18
  • GoldRush18
ok im still on part 2 when it comes to graph and stuff i just cant get it thanks though
experimentX
  • experimentX
you know how to find slope ... ?? from two points??
GoldRush18
  • GoldRush18
nope
GoldRush18
  • GoldRush18
is that the same thing as the gradient
experimentX
  • experimentX
yes ... \[ m = \frac{y_2 - y_1}{x_2 - x_1}\]
GoldRush18
  • GoldRush18
and i got 4/3
experimentX
  • experimentX
allright you know when two lines are perpendicular, if m1 and m2 be their gradient or slope then \( m_1 * m_2 = -1\) ??
GoldRush18
  • GoldRush18
no i didnt know that so what are the values i should include for this part
experimentX
  • experimentX
m1 is just you calculated ... slope(gradient) of that radius!! m2 .. you have to calculate!! using the relation above.
GoldRush18
  • GoldRush18
i got 0
experimentX
  • experimentX
http://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/v/perpendicular-lines?playlist=Algebra+I+Worked+Examples http://www.mathopenref.com/coordperpendicular.html I am not sure if it will help!!
experimentX
  • experimentX
No .. you should get m1*m2 = -1 (m1 = 4/3) m2 = -3/4
GoldRush18
  • GoldRush18
ok i got it now
GoldRush18
  • GoldRush18
how do i get C which is the y intercept?
experimentX
  • experimentX
you know one point ... so it satisfies that equation m = -3/4 (x,y) = (6,8) y = mx+c, c=??
GoldRush18
  • GoldRush18
i got y=-3/4x+25/2
experimentX
  • experimentX
Oo .. put the values of x=6 and y=8 since (x,y) is solution and we already know this!!
GoldRush18
  • GoldRush18
ok i understand now
GoldRush18
  • GoldRush18
im gonna try part c
GoldRush18
  • GoldRush18
and im stuck once more
experimentX
  • experimentX
put y = 2x+3 on (x-3)^2+(y-4)^2=25 and find the value of x

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