Here's the question you clicked on:
GoldRush18
The points P and Q have position vectors relative to the origin O given respectively by p=-i+6j and q=3i+8j. i. a) Calculate in degrees the size of the acute angle between p and q. b)hence, calculate the area of the triangle POQ ii Find in terms of i and j, the position vector of a) M, where M is the midpoint of PQ. b) R. where R is such that PQRO, labelled clockwise, forms a parallelogram.
To find the angle between vectors the dot product relation is used. \[\cos \theta=\frac{p*q}{\left| p \right|\left| q \right|}\]
So, this gives:\[\cos \theta=\frac{-3+48}{\sqrt{7}\sqrt{73}}\]\[\theta \approx75.15 \]degrees.
You should be able to get the area of the triangle POQ now
let me know what you have so far
ok the page keeps refreshing thats why my replies are late
yeah sometimes this site chugs along bad
ah crap I made an error. the length of vector p should be sqrt(1+36)=sqrt(37)
ok im still working on the question
So the angle should be about 30 degrees
I got to get ready for work...good luck!
ok thanks so far bye