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Describe the differences between the graph of y = –3(x + 7)2 – 10 and the standard position graph of y = x2.
 one year ago
 one year ago
Describe the differences between the graph of y = –3(x + 7)2 – 10 and the standard position graph of y = x2.
 one year ago
 one year ago

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Brent0423Best ResponseYou've already chosen the best response.0
please indicate whether its a 2 or a squared "(x+7)2"
 one year ago

bridgetolivaresBest ResponseYou've already chosen the best response.0
yes it is squared
 one year ago

zeppBest ResponseYou've already chosen the best response.1
The parabola could be written as \(y = a(b(xh)^2 + k\) Where, a,b,h,k are some constants.
 one year ago

zeppBest ResponseYou've already chosen the best response.1
a describes the vertical stretch; b describes the horizontal stretch; (h,k) is the vertex.
 one year ago

zeppBest ResponseYou've already chosen the best response.1
In your parabole, can you identify a,b,h and k for me? :)
 one year ago

Brent0423Best ResponseYou've already chosen the best response.0
y = –3(x + 7)^2 – 10 y=3(x^2+49)10 y=3x^214710 y=3x^2157 since the 3 is negative it indicate that the graph opens downward *NOTE* if the number before the x^2 is negative the graph opens downwards, if it is positive then it opens upwards the graph y=x^2 isnt this just y=1x^2 1 is positive so the parabola opens upwards INSTEAD of downwards.
 one year ago

zeppBest ResponseYou've already chosen the best response.1
@Brent0423 (x+7)^2 doesn't give x^2 + 49, it gives x^2 + 14x + 49.
 one year ago

zeppBest ResponseYou've already chosen the best response.1
As \((a+b)^2\ = a^2 + 2ab+b^2\)
 one year ago

Brent0423Best ResponseYou've already chosen the best response.0
oops thought i put that, sorry
 one year ago

Brent0423Best ResponseYou've already chosen the best response.0
you can still see the difference in the graphs just by looking at the number in front of the x^2
 one year ago

zeppBest ResponseYou've already chosen the best response.1
Let me find a,b,h,k for you :) y = –3(x + 7)^2 – 10 > y = –3(x  (7))^2 – 10 (Notice the negative!) 3 would be a, the vertical stretch 1 would be b, since there's nothing in front of x Vertex would be at (7, 10) Now let's take a look at our basic parabola, y = x^2 a = 1 b = 1 Vertex: (0,0) Since our a constant is a negative number AND greater than 1, we can say that this function has been stretch vertically of factor 3. Then b is the same. Vertex (0,0) and (7,10) We can say that the parabola is moved of 7 to the left and 10 downward.
 one year ago
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