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bridgetolivares
 3 years ago
Describe the differences between the graph of y = –3(x + 7)2 – 10 and the standard position graph of y = x2.
bridgetolivares
 3 years ago
Describe the differences between the graph of y = –3(x + 7)2 – 10 and the standard position graph of y = x2.

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Brent0423
 3 years ago
Best ResponseYou've already chosen the best response.0please indicate whether its a 2 or a squared "(x+7)2"

bridgetolivares
 3 years ago
Best ResponseYou've already chosen the best response.0yes it is squared

zepp
 3 years ago
Best ResponseYou've already chosen the best response.1The parabola could be written as \(y = a(b(xh)^2 + k\) Where, a,b,h,k are some constants.

zepp
 3 years ago
Best ResponseYou've already chosen the best response.1a describes the vertical stretch; b describes the horizontal stretch; (h,k) is the vertex.

zepp
 3 years ago
Best ResponseYou've already chosen the best response.1In your parabole, can you identify a,b,h and k for me? :)

Brent0423
 3 years ago
Best ResponseYou've already chosen the best response.0y = –3(x + 7)^2 – 10 y=3(x^2+49)10 y=3x^214710 y=3x^2157 since the 3 is negative it indicate that the graph opens downward *NOTE* if the number before the x^2 is negative the graph opens downwards, if it is positive then it opens upwards the graph y=x^2 isnt this just y=1x^2 1 is positive so the parabola opens upwards INSTEAD of downwards.

zepp
 3 years ago
Best ResponseYou've already chosen the best response.1@Brent0423 (x+7)^2 doesn't give x^2 + 49, it gives x^2 + 14x + 49.

zepp
 3 years ago
Best ResponseYou've already chosen the best response.1As \((a+b)^2\ = a^2 + 2ab+b^2\)

Brent0423
 3 years ago
Best ResponseYou've already chosen the best response.0oops thought i put that, sorry

Brent0423
 3 years ago
Best ResponseYou've already chosen the best response.0you can still see the difference in the graphs just by looking at the number in front of the x^2

zepp
 3 years ago
Best ResponseYou've already chosen the best response.1Let me find a,b,h,k for you :) y = –3(x + 7)^2 – 10 > y = –3(x  (7))^2 – 10 (Notice the negative!) 3 would be a, the vertical stretch 1 would be b, since there's nothing in front of x Vertex would be at (7, 10) Now let's take a look at our basic parabola, y = x^2 a = 1 b = 1 Vertex: (0,0) Since our a constant is a negative number AND greater than 1, we can say that this function has been stretch vertically of factor 3. Then b is the same. Vertex (0,0) and (7,10) We can say that the parabola is moved of 7 to the left and 10 downward.
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