anonymous
  • anonymous
if x+sqrt(x)=1 what is the value of x^2+2x.sqrt(x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[x+\sqrt{x}=1\] \[\sqrt{x}=1-x\]x^2-3x+1=0 \[x=1-2x+x^2\] \[x^2-3x+1=0\] \[x=\frac{3-\sqrt{5}}{2}\] and \[1=(x+\sqrt{x})^2=x^2+2x\sqrt{x}+x\]so \[x^2+2\sqrt{x}=1-\frac{3-\sqrt{5}}{2}=\frac{2-3+\sqrt{5}}{2}=\frac{-1+\sqrt{5}}{2}\]
anonymous
  • anonymous
where did you get x^2-3x+1=0 from? Oo
anonymous
  • anonymous
\[\sqrt{x}=1-x\] square both sides get \[x=(1-x)^2=1-2x+x^2\] set equal to zero to solve the quadratic get \[x^2-3x+1=0\] unless i goofed up

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anonymous
  • anonymous
no, you're right, i just didn't pay attention :P
anonymous
  • anonymous
you really in brazil?!
anonymous
  • anonymous
haha yeah lol
anonymous
  • anonymous
wow.
anonymous
  • anonymous
near the ocean?
anonymous
  • anonymous
10 min :P
anonymous
  • anonymous
nice
anonymous
  • anonymous
so if i sometimes say something wrong in my questions, it's becaus i have to translate them all :)
anonymous
  • anonymous
from portuguese?
anonymous
  • anonymous
yup. all of them :)
anonymous
  • anonymous
i am impressed
anonymous
  • anonymous
be
anonymous
  • anonymous
why not? i can barely speak one language, and portuguese is way different than english
anonymous
  • anonymous
yeah but i lived in england for a few years when i was little, so i still remember a few things. The hard part is to know scientific words, but MIT open course helps me with that lol
anonymous
  • anonymous
i bet brazil in nicer than england
anonymous
  • anonymous
no way, i'm doing everything to go back. where are you from?
anonymous
  • anonymous
philadelphia
anonymous
  • anonymous
going back when you graduate? or sooner?
anonymous
  • anonymous
sooner, my dad works in reasearch and he knows a lot of people at some universities in england so i might try to get a transfer or something when he goes there to do his Post-doc
anonymous
  • anonymous
good luck! hope you get there soon.
anonymous
  • anonymous
thank you :)

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