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ashwinjohn3
Ifp,q are rational and 2+\[\sqrt{3}\] is a root of x^2+px+q=0 then find the values of p and q.
if 2+sqrt3 is a root then 2-sqrt3 is also root, so sum of roots is 4=-b/a
when roots are irrational, they occur as conjugate surds --> that means if one root of the quadratic is 2+sqrt3, the other would be 2-sqrt3. Hence, you can find out product of roots, which is 'q'. and sum of roots which is '-p'.
and multilpy root is 1= c/a=q
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this question asked 3 months ago !!!!!