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dpaInc Group TitleBest ResponseYou've already chosen the best response.1
hmm... is that e^(ix) + e^(ix) so = 2e^(ix) on the right side?
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.0
\[\cos(x)=\frac{e^{ix}+e^{ix}}{2} \]
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.0
that means I can split cos(x) into two different functions right?
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
what do you mean split up cosx ? that looks a bit like the hperbolic coshx...
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.0
Well there is a problem where I try to show if cos(x) is an eigenfunction of an operator. I did the operation and found out it wasn't but then my book says if it's not a the eigenfunction that it must be a superposition eigenfunction so it splits it into two functions. I just dont see how it splits or how this superposition will be the eigenfunction.
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.0
Can you at least show me how \[\cos(x)=\frac{e^{ix}+e^{ix}}{2} \]
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
this is guess, but try doing the series expansion for e^(ix) + e^(ix). i have a feeling the imaginary terms will cancel.
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.0
Write e^ix =cos(x)+i sin(x)
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.1
e^(ix) = cos x + i sin x (Euler's Formula) e^(ix) = cos(x) + i sin (x) = cos x i sin x Add them.
 2 years ago
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