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 2 years ago
the circle C1 has (3,4) and (1,2) as endpoints of a diameter.
i. Show that the equation of C1 is x^2+y^2+2x6y+5=0.
ii. The Circle C2 has equation x^2+y^2+x5y=0. Calculate the coordinates of the point of intersection of C1 and C2
 2 years ago
the circle C1 has (3,4) and (1,2) as endpoints of a diameter. i. Show that the equation of C1 is x^2+y^2+2x6y+5=0. ii. The Circle C2 has equation x^2+y^2+x5y=0. Calculate the coordinates of the point of intersection of C1 and C2

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1729antony
 2 years ago
Best ResponseYou've already chosen the best response.1since the 2 points are the end points of diameter center is given by (3+1)/2 ,(4+2)/2=(1,3)..and radius = sqrt ((1+3)^2+(34)^2)=sqrt 5..so circle equation is (x+1)^2 +(y3)^2=5 simplifying x^2+y^2+2x6y+5=0.
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