Here's the question you clicked on:
audreygator912
The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X. What is the measure of angle ACB? 6, 12, 24 or 32 degrees
@pfenn1 can you help me please?
@Kris5, could you show how you got the answer, not just the answer?
Sure, <XBA is an inscribed angle. Therefore, it is twice the measure of its intercepted arc. Its intercepted arc is arc XA. So... arc XA= 2m<XBA... arc XA=2(64)...arc XA=128. Now< ACB= 1/2 (BA-XA)... <ACB=1/2(152-128)...<ACB=1/2(24)...<ACB=12 :)