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x is suppose to be down, oops.

http://www.wolframalpha.com/input/?i=is+%281-cos2x%29%281%2Btan2x%29+equal+to+tan2x

false? .. oh.

how would I know when it's false on a test?

i don't understand..

sin(x) = cos(pi/2 - x) <---- put any value of x, you will always find it true!!

LOL .. i found it a little while ago

Why not just expand the left side and do some cancelling?

that's what I tried but then there's going to be no sinx at the bottom?

\( (\tan2x + 1) - (\tan2x+1)\cos2x = \tan 2x \)
\( \implies 1 - (\tan2x+1)\cos2x = 0 \)