At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

Wel, first isolate the term for v^2

*first isolate v^2

(divide by 4, if you don't know)

ok

S/4=v^2

ok

Then, take the plus-minus square root of both sides.

You know how to simplify
\(\Huge \pm\sqrt\frac{S}{4}\) right?

ok im following you

Let me show you the whole thing. ONe sec, this may take a minute or two.

ok im waiting :)

I can try........ I dont remember how to do any of ths... I'm sooo lost!

Alright, it's ok. Just tell me which steps you don't understand :)

I honestly need help with the whole problem, im soooo confused! :'(

It's the problem itself, I just don't understand :'(

Note that v can ONLY be on one side. If you have v on both sides, it's a mistake.

okay, im following you so far!

Good. :)

i have solved it before - not is clearly there ?

Now, do you remember how we move things around?

Like, combine like terms, move things from one side to the other, and take square roots?

ok well can you show me how? Like the steps ??

Ok. In general, or just for this equation?

just the steps on how to solve this problem... The problem told me to show my work.......

Okk.

okay so what would I do then?

What's in front of v?

1.Solve S = 4v2 for v.

I mean, what's in front of "v^2"?

So, how do we move the 4 to the other side?

-4(4-4)=-2(2v-1)

Not that complicated. Just divide both sides by 4 :)

Is the answer to the question v=2?

Well, we can't actually solve for an exact value of v. We can only express it in terms of "s".

okay, I'm sooo confused!!! :'(

OMG!!! dumb right now :(

Ok. If you have the equation x-2y=0 you can't find x, because you don't know y.

okay, I understand that, I just don''t understand on how to solve this problem!

ok,im following so far.

ok so S/4=4v^2/4

Ok. Now simplify the rigt side.

S=v^2

Careful, you can't cancel out the left side...

S/4=v^2

yess.

Now, what do we do to get rid of v^2? (turn it into v)

S/4=v

Careful. You have to take the square root of BOTH sides.

I got confused, just now. I beeen following this whole time and i just now got lost!!! :'(

That's ok.

S/4=4v^2/4
-> \(\huge \frac{S}{4}=\frac{(4v^2)}{4}\)

Then
\(\Huge \frac{S}{4}=v^2\)

Now, here's the part you got lost. Let me show it in more detail.

\(\Huge \pm\sqrt{\frac{S}{4}}=\sqrt{v^2}\)

There's a lot going on right here.

Does everything make sense?

ima little lost there

Ok.
Do you know why we have the plus minus sign?

nope, im confused whole step.......

damn, what time is it there?

dang........

ACtually, I'm going to take both right now. No chances.

ok, im following so far.

Brittany, I can help too, becaues I just realized I only have one test.

\(\huge v=\pm\frac{\sqrt{S}}{\sqrt{4}}\)

Remember,
\(\Huge \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\)

Now, what's the square root of 4?

Ok, then, what do we get?

(use draw if you have to)

\(v=\pm\dfrac{\sqrt{S}}{\sqrt{4}}\), \(\sqrt{4}=2\), so \(v=?\)

@brittany_lundgren , do you get it?