anonymous
  • anonymous
1.Solve S = 4v2 for v. Show your work
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
inkyvoyd
  • inkyvoyd
Wel, first isolate the term for v^2
inkyvoyd
  • inkyvoyd
*first isolate v^2
inkyvoyd
  • inkyvoyd
(divide by 4, if you don't know)

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anonymous
  • anonymous
ok
inkyvoyd
  • inkyvoyd
S/4=v^2
anonymous
  • anonymous
ok
inkyvoyd
  • inkyvoyd
Then, take the plus-minus square root of both sides.
inkyvoyd
  • inkyvoyd
You know how to simplify \(\Huge \pm\sqrt\frac{S}{4}\) right?
anonymous
  • anonymous
ok im following you
inkyvoyd
  • inkyvoyd
Let me show you the whole thing. ONe sec, this may take a minute or two.
anonymous
  • anonymous
ok im waiting :)
inkyvoyd
  • inkyvoyd
S = 4v2 \(\Large S=4v^2\) ->Isolate the "\(v^2\)" \(\Large \frac{S}{4}=v^2\) Take the positive negative square root of both sides \(\huge \pm\sqrt{\frac{S}{4}}=v\) \(\huge \pm\frac{\sqrt{S}}{\sqrt{4}}=v\) Can you try from here?
inkyvoyd
  • inkyvoyd
@brittany_lundgren ?
anonymous
  • anonymous
I can try........ I dont remember how to do any of ths... I'm sooo lost!
inkyvoyd
  • inkyvoyd
Alright, it's ok. Just tell me which steps you don't understand :)
anonymous
  • anonymous
I honestly need help with the whole problem, im soooo confused! :'(
inkyvoyd
  • inkyvoyd
Ok, so, from step one, right? Which parts of step one do you not understand? Or is it the problem itself?
anonymous
  • anonymous
It's the problem itself, I just don't understand :'(
inkyvoyd
  • inkyvoyd
Ok, what they do is give you an equation. What they want you to do is to "solve for v" This means they want you to put v on one side, and everything else on the other.
inkyvoyd
  • inkyvoyd
Note that v can ONLY be on one side. If you have v on both sides, it's a mistake.
anonymous
  • anonymous
okay, im following you so far!
inkyvoyd
  • inkyvoyd
Good. :)
jhonyy9
  • jhonyy9
i have solved it before - not is clearly there ?
inkyvoyd
  • inkyvoyd
Now, do you remember how we move things around?
inkyvoyd
  • inkyvoyd
Like, combine like terms, move things from one side to the other, and take square roots?
anonymous
  • anonymous
ok well can you show me how? Like the steps ??
inkyvoyd
  • inkyvoyd
Ok. In general, or just for this equation?
anonymous
  • anonymous
just the steps on how to solve this problem... The problem told me to show my work.......
inkyvoyd
  • inkyvoyd
Okk.
inkyvoyd
  • inkyvoyd
Remember, we want to put "v" on one side, and everything else on the other. The first step is to get rid of what's in front of v.
anonymous
  • anonymous
okay so what would I do then?
inkyvoyd
  • inkyvoyd
What's in front of v?
anonymous
  • anonymous
1.Solve S = 4v2 for v.
inkyvoyd
  • inkyvoyd
I mean, what's in front of "v^2"?
anonymous
  • anonymous
4
inkyvoyd
  • inkyvoyd
So, how do we move the 4 to the other side?
anonymous
  • anonymous
-4(4-4)=-2(2v-1)
inkyvoyd
  • inkyvoyd
Not that complicated. Just divide both sides by 4 :)
anonymous
  • anonymous
Is the answer to the question v=2?
inkyvoyd
  • inkyvoyd
Well, we can't actually solve for an exact value of v. We can only express it in terms of "s".
anonymous
  • anonymous
okay, I'm sooo confused!!! :'(
inkyvoyd
  • inkyvoyd
Ok. We can't always solve for v (in terms of a number, like 3, or -2). But, we can move everything over to one side and leave v on the other.
anonymous
  • anonymous
OMG!!! dumb right now :(
inkyvoyd
  • inkyvoyd
Ok. If you have the equation x-2y=0 you can't find x, because you don't know y.
anonymous
  • anonymous
okay, I understand that, I just don''t understand on how to solve this problem!
inkyvoyd
  • inkyvoyd
Ok. Solve for v doesn't mean "get a number value for v". It means, "put just v on one side, and everything else without v on the other"
anonymous
  • anonymous
ok,im following so far.
inkyvoyd
  • inkyvoyd
Alright. Since we just want to move everything to the other side, we divide both sides by 4 to get rid of what's in front of v.
anonymous
  • anonymous
ok so S/4=4v^2/4
inkyvoyd
  • inkyvoyd
Ok. Now simplify the rigt side.
anonymous
  • anonymous
S=v^2
inkyvoyd
  • inkyvoyd
Careful, you can't cancel out the left side...
anonymous
  • anonymous
S/4=v^2
inkyvoyd
  • inkyvoyd
yess.
inkyvoyd
  • inkyvoyd
Now, what do we do to get rid of v^2? (turn it into v)
anonymous
  • anonymous
S/4=v
inkyvoyd
  • inkyvoyd
Careful. You have to take the square root of BOTH sides.
anonymous
  • anonymous
I got confused, just now. I beeen following this whole time and i just now got lost!!! :'(
inkyvoyd
  • inkyvoyd
That's ok.
inkyvoyd
  • inkyvoyd
S/4=4v^2/4 -> \(\huge \frac{S}{4}=\frac{(4v^2)}{4}\)
inkyvoyd
  • inkyvoyd
Then \(\Huge \frac{S}{4}=v^2\)
inkyvoyd
  • inkyvoyd
Now, here's the part you got lost. Let me show it in more detail.
inkyvoyd
  • inkyvoyd
\(\Huge \pm\sqrt{\frac{S}{4}}=\sqrt{v^2}\)
inkyvoyd
  • inkyvoyd
There's a lot going on right here.
inkyvoyd
  • inkyvoyd
Does everything make sense?
anonymous
  • anonymous
ima little lost there
inkyvoyd
  • inkyvoyd
Ok. Do you know why we have the plus minus sign?
anonymous
  • anonymous
nope, im confused whole step.......
inkyvoyd
  • inkyvoyd
I'm really sorry, but I have to go to bed. I'll try to make sure I get people here to help you. (I have to take some tests myself tomorrow, and I can't afford to miss them) @nbouscal , would you be so kind as to help out? THanks.
anonymous
  • anonymous
damn, what time is it there?
inkyvoyd
  • inkyvoyd
2:00 AM. I have to go to sleep and get done before 2:00PM, but I have two tests around 1 hour each, :S
anonymous
  • anonymous
dang........
inkyvoyd
  • inkyvoyd
ACtually, I'm going to take both right now. No chances.
inkyvoyd
  • inkyvoyd
Time for a cup of coffee. thanks, @nbouscal .
anonymous
  • anonymous
Okay, if you have \(v^2=\frac{S}{4}\), and you want to know what \(v\) is, you have to take the square root of both sides. That's the only way to get the left side to just have \(v\) by itself. The problem is, when you square root something, you always have to put a \(\pm\) sign in front, because you don't know whether it's positive or negative. For example, \(2^2=4, (-2)^2=4\), so the square root of 4 could be either 2 or -2. So, we take the square root of both sides and we add a plus-or-minus, and we get \[ v=\pm\sqrt{\frac{S}{4}} \]
anonymous
  • anonymous
@nbouscal brb imma go get something to drink
anonymous
  • anonymous
ok, im following so far.
inkyvoyd
  • inkyvoyd
Brittany, I can help too, becaues I just realized I only have one test.
inkyvoyd
  • inkyvoyd
\(\huge v=\pm\frac{\sqrt{S}}{\sqrt{4}}\)
inkyvoyd
  • inkyvoyd
Remember, \(\Huge \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\)
inkyvoyd
  • inkyvoyd
Now, what's the square root of 4?
inkyvoyd
  • inkyvoyd
(@nbouscal , I'm going to go ahead and take my scantron before the coffee wears off)
anonymous
  • anonymous
2
anonymous
  • anonymous
@inkyvoyd @nbouscal
inkyvoyd
  • inkyvoyd
Ok, then, what do we get?
inkyvoyd
  • inkyvoyd
(use draw if you have to)
anonymous
  • anonymous
\(v=\pm\dfrac{\sqrt{S}}{\sqrt{4}}\), \(\sqrt{4}=2\), so \(v=?\)
inkyvoyd
  • inkyvoyd
@brittany_lundgren , do you get it?

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