Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

1.Solve S = 4v2 for v. Show your work

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Wel, first isolate the term for v^2
*first isolate v^2
(divide by 4, if you don't know)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

ok
S/4=v^2
ok
Then, take the plus-minus square root of both sides.
You know how to simplify \(\Huge \pm\sqrt\frac{S}{4}\) right?
ok im following you
Let me show you the whole thing. ONe sec, this may take a minute or two.
ok im waiting :)
S = 4v2 \(\Large S=4v^2\) ->Isolate the "\(v^2\)" \(\Large \frac{S}{4}=v^2\) Take the positive negative square root of both sides \(\huge \pm\sqrt{\frac{S}{4}}=v\) \(\huge \pm\frac{\sqrt{S}}{\sqrt{4}}=v\) Can you try from here?
I can try........ I dont remember how to do any of ths... I'm sooo lost!
Alright, it's ok. Just tell me which steps you don't understand :)
I honestly need help with the whole problem, im soooo confused! :'(
Ok, so, from step one, right? Which parts of step one do you not understand? Or is it the problem itself?
It's the problem itself, I just don't understand :'(
Ok, what they do is give you an equation. What they want you to do is to "solve for v" This means they want you to put v on one side, and everything else on the other.
Note that v can ONLY be on one side. If you have v on both sides, it's a mistake.
okay, im following you so far!
Good. :)
i have solved it before - not is clearly there ?
Now, do you remember how we move things around?
Like, combine like terms, move things from one side to the other, and take square roots?
ok well can you show me how? Like the steps ??
Ok. In general, or just for this equation?
just the steps on how to solve this problem... The problem told me to show my work.......
Okk.
Remember, we want to put "v" on one side, and everything else on the other. The first step is to get rid of what's in front of v.
okay so what would I do then?
What's in front of v?
1.Solve S = 4v2 for v.
I mean, what's in front of "v^2"?
4
So, how do we move the 4 to the other side?
-4(4-4)=-2(2v-1)
Not that complicated. Just divide both sides by 4 :)
Is the answer to the question v=2?
Well, we can't actually solve for an exact value of v. We can only express it in terms of "s".
okay, I'm sooo confused!!! :'(
Ok. We can't always solve for v (in terms of a number, like 3, or -2). But, we can move everything over to one side and leave v on the other.
OMG!!! dumb right now :(
Ok. If you have the equation x-2y=0 you can't find x, because you don't know y.
okay, I understand that, I just don''t understand on how to solve this problem!
Ok. Solve for v doesn't mean "get a number value for v". It means, "put just v on one side, and everything else without v on the other"
ok,im following so far.
Alright. Since we just want to move everything to the other side, we divide both sides by 4 to get rid of what's in front of v.
ok so S/4=4v^2/4
Ok. Now simplify the rigt side.
S=v^2
Careful, you can't cancel out the left side...
S/4=v^2
yess.
Now, what do we do to get rid of v^2? (turn it into v)
S/4=v
Careful. You have to take the square root of BOTH sides.
I got confused, just now. I beeen following this whole time and i just now got lost!!! :'(
That's ok.
S/4=4v^2/4 -> \(\huge \frac{S}{4}=\frac{(4v^2)}{4}\)
Then \(\Huge \frac{S}{4}=v^2\)
Now, here's the part you got lost. Let me show it in more detail.
\(\Huge \pm\sqrt{\frac{S}{4}}=\sqrt{v^2}\)
There's a lot going on right here.
Does everything make sense?
ima little lost there
Ok. Do you know why we have the plus minus sign?
nope, im confused whole step.......
I'm really sorry, but I have to go to bed. I'll try to make sure I get people here to help you. (I have to take some tests myself tomorrow, and I can't afford to miss them) @nbouscal , would you be so kind as to help out? THanks.
damn, what time is it there?
2:00 AM. I have to go to sleep and get done before 2:00PM, but I have two tests around 1 hour each, :S
dang........
ACtually, I'm going to take both right now. No chances.
Time for a cup of coffee. thanks, @nbouscal .
Okay, if you have \(v^2=\frac{S}{4}\), and you want to know what \(v\) is, you have to take the square root of both sides. That's the only way to get the left side to just have \(v\) by itself. The problem is, when you square root something, you always have to put a \(\pm\) sign in front, because you don't know whether it's positive or negative. For example, \(2^2=4, (-2)^2=4\), so the square root of 4 could be either 2 or -2. So, we take the square root of both sides and we add a plus-or-minus, and we get \[ v=\pm\sqrt{\frac{S}{4}} \]
@nbouscal brb imma go get something to drink
ok, im following so far.
Brittany, I can help too, becaues I just realized I only have one test.
\(\huge v=\pm\frac{\sqrt{S}}{\sqrt{4}}\)
Remember, \(\Huge \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\)
Now, what's the square root of 4?
(@nbouscal , I'm going to go ahead and take my scantron before the coffee wears off)
2
Ok, then, what do we get?
(use draw if you have to)
\(v=\pm\dfrac{\sqrt{S}}{\sqrt{4}}\), \(\sqrt{4}=2\), so \(v=?\)
@brittany_lundgren , do you get it?

Not the answer you are looking for?

Search for more explanations.

Ask your own question