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inkyvoydBest ResponseYou've already chosen the best response.4
Wel, first isolate the term for v^2
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
(divide by 4, if you don't know)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Then, take the plusminus square root of both sides.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
You know how to simplify \(\Huge \pm\sqrt\frac{S}{4}\) right?
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
ok im following you
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Let me show you the whole thing. ONe sec, this may take a minute or two.
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
ok im waiting :)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
S = 4v2 \(\Large S=4v^2\) >Isolate the "\(v^2\)" \(\Large \frac{S}{4}=v^2\) Take the positive negative square root of both sides \(\huge \pm\sqrt{\frac{S}{4}}=v\) \(\huge \pm\frac{\sqrt{S}}{\sqrt{4}}=v\) Can you try from here?
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
I can try........ I dont remember how to do any of ths... I'm sooo lost!
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Alright, it's ok. Just tell me which steps you don't understand :)
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
I honestly need help with the whole problem, im soooo confused! :'(
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Ok, so, from step one, right? Which parts of step one do you not understand? Or is it the problem itself?
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
It's the problem itself, I just don't understand :'(
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Ok, what they do is give you an equation. What they want you to do is to "solve for v" This means they want you to put v on one side, and everything else on the other.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Note that v can ONLY be on one side. If you have v on both sides, it's a mistake.
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
okay, im following you so far!
 one year ago

jhonyy9Best ResponseYou've already chosen the best response.0
i have solved it before  not is clearly there ?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Now, do you remember how we move things around?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Like, combine like terms, move things from one side to the other, and take square roots?
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
ok well can you show me how? Like the steps ??
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Ok. In general, or just for this equation?
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
just the steps on how to solve this problem... The problem told me to show my work.......
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Remember, we want to put "v" on one side, and everything else on the other. The first step is to get rid of what's in front of v.
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
okay so what would I do then?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
What's in front of v?
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
1.Solve S = 4v2 for v.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
I mean, what's in front of "v^2"?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
So, how do we move the 4 to the other side?
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
4(44)=2(2v1)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Not that complicated. Just divide both sides by 4 :)
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
Is the answer to the question v=2?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Well, we can't actually solve for an exact value of v. We can only express it in terms of "s".
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
okay, I'm sooo confused!!! :'(
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Ok. We can't always solve for v (in terms of a number, like 3, or 2). But, we can move everything over to one side and leave v on the other.
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
OMG!!! dumb right now :(
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Ok. If you have the equation x2y=0 you can't find x, because you don't know y.
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
okay, I understand that, I just don''t understand on how to solve this problem!
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Ok. Solve for v doesn't mean "get a number value for v". It means, "put just v on one side, and everything else without v on the other"
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
ok,im following so far.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Alright. Since we just want to move everything to the other side, we divide both sides by 4 to get rid of what's in front of v.
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
ok so S/4=4v^2/4
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Ok. Now simplify the rigt side.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Careful, you can't cancel out the left side...
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Now, what do we do to get rid of v^2? (turn it into v)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Careful. You have to take the square root of BOTH sides.
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
I got confused, just now. I beeen following this whole time and i just now got lost!!! :'(
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
S/4=4v^2/4 > \(\huge \frac{S}{4}=\frac{(4v^2)}{4}\)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Then \(\Huge \frac{S}{4}=v^2\)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Now, here's the part you got lost. Let me show it in more detail.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
\(\Huge \pm\sqrt{\frac{S}{4}}=\sqrt{v^2}\)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
There's a lot going on right here.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Does everything make sense?
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
ima little lost there
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Ok. Do you know why we have the plus minus sign?
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
nope, im confused whole step.......
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
I'm really sorry, but I have to go to bed. I'll try to make sure I get people here to help you. (I have to take some tests myself tomorrow, and I can't afford to miss them) @nbouscal , would you be so kind as to help out? THanks.
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
damn, what time is it there?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
2:00 AM. I have to go to sleep and get done before 2:00PM, but I have two tests around 1 hour each, :S
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
dang........
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
ACtually, I'm going to take both right now. No chances.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Time for a cup of coffee. thanks, @nbouscal .
 one year ago

nbouscalBest ResponseYou've already chosen the best response.1
Okay, if you have \(v^2=\frac{S}{4}\), and you want to know what \(v\) is, you have to take the square root of both sides. That's the only way to get the left side to just have \(v\) by itself. The problem is, when you square root something, you always have to put a \(\pm\) sign in front, because you don't know whether it's positive or negative. For example, \(2^2=4, (2)^2=4\), so the square root of 4 could be either 2 or 2. So, we take the square root of both sides and we add a plusorminus, and we get \[ v=\pm\sqrt{\frac{S}{4}} \]
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
@nbouscal brb imma go get something to drink
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
ok, im following so far.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Brittany, I can help too, becaues I just realized I only have one test.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
\(\huge v=\pm\frac{\sqrt{S}}{\sqrt{4}}\)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Remember, \(\Huge \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Now, what's the square root of 4?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
(@nbouscal , I'm going to go ahead and take my scantron before the coffee wears off)
 one year ago

brittany_lundgrenBest ResponseYou've already chosen the best response.0
@inkyvoyd @nbouscal
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
Ok, then, what do we get?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
(use draw if you have to)
 one year ago

nbouscalBest ResponseYou've already chosen the best response.1
\(v=\pm\dfrac{\sqrt{S}}{\sqrt{4}}\), \(\sqrt{4}=2\), so \(v=?\)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.4
@brittany_lundgren , do you get it?
 one year ago
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