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anonymous
 4 years ago
1.Solve S = 4v2 for v.
Show your work
anonymous
 4 years ago
1.Solve S = 4v2 for v. Show your work

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inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Wel, first isolate the term for v^2

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4(divide by 4, if you don't know)

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Then, take the plusminus square root of both sides.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4You know how to simplify \(\Huge \pm\sqrt\frac{S}{4}\) right?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Let me show you the whole thing. ONe sec, this may take a minute or two.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4S = 4v2 \(\Large S=4v^2\) >Isolate the "\(v^2\)" \(\Large \frac{S}{4}=v^2\) Take the positive negative square root of both sides \(\huge \pm\sqrt{\frac{S}{4}}=v\) \(\huge \pm\frac{\sqrt{S}}{\sqrt{4}}=v\) Can you try from here?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I can try........ I dont remember how to do any of ths... I'm sooo lost!

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Alright, it's ok. Just tell me which steps you don't understand :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I honestly need help with the whole problem, im soooo confused! :'(

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Ok, so, from step one, right? Which parts of step one do you not understand? Or is it the problem itself?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's the problem itself, I just don't understand :'(

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Ok, what they do is give you an equation. What they want you to do is to "solve for v" This means they want you to put v on one side, and everything else on the other.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Note that v can ONLY be on one side. If you have v on both sides, it's a mistake.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, im following you so far!

jhonyy9
 4 years ago
Best ResponseYou've already chosen the best response.0i have solved it before  not is clearly there ?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Now, do you remember how we move things around?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Like, combine like terms, move things from one side to the other, and take square roots?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok well can you show me how? Like the steps ??

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Ok. In general, or just for this equation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just the steps on how to solve this problem... The problem told me to show my work.......

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Remember, we want to put "v" on one side, and everything else on the other. The first step is to get rid of what's in front of v.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay so what would I do then?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01.Solve S = 4v2 for v.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4I mean, what's in front of "v^2"?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4So, how do we move the 4 to the other side?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Not that complicated. Just divide both sides by 4 :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is the answer to the question v=2?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Well, we can't actually solve for an exact value of v. We can only express it in terms of "s".

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, I'm sooo confused!!! :'(

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Ok. We can't always solve for v (in terms of a number, like 3, or 2). But, we can move everything over to one side and leave v on the other.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OMG!!! dumb right now :(

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Ok. If you have the equation x2y=0 you can't find x, because you don't know y.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, I understand that, I just don''t understand on how to solve this problem!

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Ok. Solve for v doesn't mean "get a number value for v". It means, "put just v on one side, and everything else without v on the other"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok,im following so far.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Alright. Since we just want to move everything to the other side, we divide both sides by 4 to get rid of what's in front of v.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Ok. Now simplify the rigt side.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Careful, you can't cancel out the left side...

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Now, what do we do to get rid of v^2? (turn it into v)

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Careful. You have to take the square root of BOTH sides.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got confused, just now. I beeen following this whole time and i just now got lost!!! :'(

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4S/4=4v^2/4 > \(\huge \frac{S}{4}=\frac{(4v^2)}{4}\)

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Then \(\Huge \frac{S}{4}=v^2\)

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Now, here's the part you got lost. Let me show it in more detail.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4\(\Huge \pm\sqrt{\frac{S}{4}}=\sqrt{v^2}\)

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4There's a lot going on right here.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Does everything make sense?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ima little lost there

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Ok. Do you know why we have the plus minus sign?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nope, im confused whole step.......

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4I'm really sorry, but I have to go to bed. I'll try to make sure I get people here to help you. (I have to take some tests myself tomorrow, and I can't afford to miss them) @nbouscal , would you be so kind as to help out? THanks.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0damn, what time is it there?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.42:00 AM. I have to go to sleep and get done before 2:00PM, but I have two tests around 1 hour each, :S

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4ACtually, I'm going to take both right now. No chances.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Time for a cup of coffee. thanks, @nbouscal .

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, if you have \(v^2=\frac{S}{4}\), and you want to know what \(v\) is, you have to take the square root of both sides. That's the only way to get the left side to just have \(v\) by itself. The problem is, when you square root something, you always have to put a \(\pm\) sign in front, because you don't know whether it's positive or negative. For example, \(2^2=4, (2)^2=4\), so the square root of 4 could be either 2 or 2. So, we take the square root of both sides and we add a plusorminus, and we get \[ v=\pm\sqrt{\frac{S}{4}} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@nbouscal brb imma go get something to drink

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, im following so far.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Brittany, I can help too, becaues I just realized I only have one test.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4\(\huge v=\pm\frac{\sqrt{S}}{\sqrt{4}}\)

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Remember, \(\Huge \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\)

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Now, what's the square root of 4?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4(@nbouscal , I'm going to go ahead and take my scantron before the coffee wears off)

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4Ok, then, what do we get?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4(use draw if you have to)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\(v=\pm\dfrac{\sqrt{S}}{\sqrt{4}}\), \(\sqrt{4}=2\), so \(v=?\)

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.4@brittany_lundgren , do you get it?
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