Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

brittany_lundgren Group Title

1.Solve S = 4v2 for v. Show your work

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Wel, first isolate the term for v^2

    • 2 years ago
  2. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    *first isolate v^2

    • 2 years ago
  3. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    (divide by 4, if you don't know)

    • 2 years ago
  4. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok

    • 2 years ago
  5. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    S/4=v^2

    • 2 years ago
  6. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok

    • 2 years ago
  7. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Then, take the plus-minus square root of both sides.

    • 2 years ago
  8. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    You know how to simplify \(\Huge \pm\sqrt\frac{S}{4}\) right?

    • 2 years ago
  9. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok im following you

    • 2 years ago
  10. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Let me show you the whole thing. ONe sec, this may take a minute or two.

    • 2 years ago
  11. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok im waiting :)

    • 2 years ago
  12. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    S = 4v2 \(\Large S=4v^2\) ->Isolate the "\(v^2\)" \(\Large \frac{S}{4}=v^2\) Take the positive negative square root of both sides \(\huge \pm\sqrt{\frac{S}{4}}=v\) \(\huge \pm\frac{\sqrt{S}}{\sqrt{4}}=v\) Can you try from here?

    • 2 years ago
  13. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    @brittany_lundgren ?

    • 2 years ago
  14. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    I can try........ I dont remember how to do any of ths... I'm sooo lost!

    • 2 years ago
  15. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Alright, it's ok. Just tell me which steps you don't understand :)

    • 2 years ago
  16. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    I honestly need help with the whole problem, im soooo confused! :'(

    • 2 years ago
  17. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Ok, so, from step one, right? Which parts of step one do you not understand? Or is it the problem itself?

    • 2 years ago
  18. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    It's the problem itself, I just don't understand :'(

    • 2 years ago
  19. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Ok, what they do is give you an equation. What they want you to do is to "solve for v" This means they want you to put v on one side, and everything else on the other.

    • 2 years ago
  20. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Note that v can ONLY be on one side. If you have v on both sides, it's a mistake.

    • 2 years ago
  21. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    okay, im following you so far!

    • 2 years ago
  22. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Good. :)

    • 2 years ago
  23. jhonyy9 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i have solved it before - not is clearly there ?

    • 2 years ago
  24. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Now, do you remember how we move things around?

    • 2 years ago
  25. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Like, combine like terms, move things from one side to the other, and take square roots?

    • 2 years ago
  26. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok well can you show me how? Like the steps ??

    • 2 years ago
  27. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Ok. In general, or just for this equation?

    • 2 years ago
  28. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    just the steps on how to solve this problem... The problem told me to show my work.......

    • 2 years ago
  29. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Okk.

    • 2 years ago
  30. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Remember, we want to put "v" on one side, and everything else on the other. The first step is to get rid of what's in front of v.

    • 2 years ago
  31. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    okay so what would I do then?

    • 2 years ago
  32. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    What's in front of v?

    • 2 years ago
  33. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    1.Solve S = 4v2 for v.

    • 2 years ago
  34. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    I mean, what's in front of "v^2"?

    • 2 years ago
  35. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    4

    • 2 years ago
  36. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    So, how do we move the 4 to the other side?

    • 2 years ago
  37. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    -4(4-4)=-2(2v-1)

    • 2 years ago
  38. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Not that complicated. Just divide both sides by 4 :)

    • 2 years ago
  39. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Is the answer to the question v=2?

    • 2 years ago
  40. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Well, we can't actually solve for an exact value of v. We can only express it in terms of "s".

    • 2 years ago
  41. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    okay, I'm sooo confused!!! :'(

    • 2 years ago
  42. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Ok. We can't always solve for v (in terms of a number, like 3, or -2). But, we can move everything over to one side and leave v on the other.

    • 2 years ago
  43. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    OMG!!! dumb right now :(

    • 2 years ago
  44. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Ok. If you have the equation x-2y=0 you can't find x, because you don't know y.

    • 2 years ago
  45. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    okay, I understand that, I just don''t understand on how to solve this problem!

    • 2 years ago
  46. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Ok. Solve for v doesn't mean "get a number value for v". It means, "put just v on one side, and everything else without v on the other"

    • 2 years ago
  47. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok,im following so far.

    • 2 years ago
  48. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Alright. Since we just want to move everything to the other side, we divide both sides by 4 to get rid of what's in front of v.

    • 2 years ago
  49. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok so S/4=4v^2/4

    • 2 years ago
  50. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Ok. Now simplify the rigt side.

    • 2 years ago
  51. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    S=v^2

    • 2 years ago
  52. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Careful, you can't cancel out the left side...

    • 2 years ago
  53. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    S/4=v^2

    • 2 years ago
  54. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    yess.

    • 2 years ago
  55. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Now, what do we do to get rid of v^2? (turn it into v)

    • 2 years ago
  56. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    S/4=v

    • 2 years ago
  57. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Careful. You have to take the square root of BOTH sides.

    • 2 years ago
  58. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    I got confused, just now. I beeen following this whole time and i just now got lost!!! :'(

    • 2 years ago
  59. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    That's ok.

    • 2 years ago
  60. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    S/4=4v^2/4 -> \(\huge \frac{S}{4}=\frac{(4v^2)}{4}\)

    • 2 years ago
  61. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Then \(\Huge \frac{S}{4}=v^2\)

    • 2 years ago
  62. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Now, here's the part you got lost. Let me show it in more detail.

    • 2 years ago
  63. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    \(\Huge \pm\sqrt{\frac{S}{4}}=\sqrt{v^2}\)

    • 2 years ago
  64. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    There's a lot going on right here.

    • 2 years ago
  65. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Does everything make sense?

    • 2 years ago
  66. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ima little lost there

    • 2 years ago
  67. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Ok. Do you know why we have the plus minus sign?

    • 2 years ago
  68. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    nope, im confused whole step.......

    • 2 years ago
  69. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    I'm really sorry, but I have to go to bed. I'll try to make sure I get people here to help you. (I have to take some tests myself tomorrow, and I can't afford to miss them) @nbouscal , would you be so kind as to help out? THanks.

    • 2 years ago
  70. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    damn, what time is it there?

    • 2 years ago
  71. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    2:00 AM. I have to go to sleep and get done before 2:00PM, but I have two tests around 1 hour each, :S

    • 2 years ago
  72. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    dang........

    • 2 years ago
  73. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    ACtually, I'm going to take both right now. No chances.

    • 2 years ago
  74. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Time for a cup of coffee. thanks, @nbouscal .

    • 2 years ago
  75. nbouscal Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Okay, if you have \(v^2=\frac{S}{4}\), and you want to know what \(v\) is, you have to take the square root of both sides. That's the only way to get the left side to just have \(v\) by itself. The problem is, when you square root something, you always have to put a \(\pm\) sign in front, because you don't know whether it's positive or negative. For example, \(2^2=4, (-2)^2=4\), so the square root of 4 could be either 2 or -2. So, we take the square root of both sides and we add a plus-or-minus, and we get \[ v=\pm\sqrt{\frac{S}{4}} \]

    • 2 years ago
  76. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @nbouscal brb imma go get something to drink

    • 2 years ago
  77. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok, im following so far.

    • 2 years ago
  78. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Brittany, I can help too, becaues I just realized I only have one test.

    • 2 years ago
  79. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    \(\huge v=\pm\frac{\sqrt{S}}{\sqrt{4}}\)

    • 2 years ago
  80. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Remember, \(\Huge \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\)

    • 2 years ago
  81. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Now, what's the square root of 4?

    • 2 years ago
  82. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    (@nbouscal , I'm going to go ahead and take my scantron before the coffee wears off)

    • 2 years ago
  83. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    2

    • 2 years ago
  84. brittany_lundgren Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @inkyvoyd @nbouscal

    • 2 years ago
  85. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    Ok, then, what do we get?

    • 2 years ago
  86. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    (use draw if you have to)

    • 2 years ago
  87. nbouscal Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \(v=\pm\dfrac{\sqrt{S}}{\sqrt{4}}\), \(\sqrt{4}=2\), so \(v=?\)

    • 2 years ago
  88. inkyvoyd Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    @brittany_lundgren , do you get it?

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.