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sydneygill14

Identify the 12th term of a geometric sequence where a1 = 8 and a6 = –8,192.

  • one year ago
  • one year ago

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  1. tmauldin
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    do you have a2

    • one year ago
  2. sydneygill14
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    no i dont

    • one year ago
  3. amistre64
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    since youve gone thru this with alot of people already ... what is the general equation for an arith. progression ?

    • one year ago
  4. tmauldin
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    a2=-32

    • one year ago
  5. tmauldin
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    an= ar1 * r^(n-1) this is the geometric equation

    • one year ago
  6. amistre64
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    lol ... its just too easy to read over that word :) yes, this is a geo ... good eye

    • one year ago
  7. tmauldin
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    lol, i see it now

    • one year ago
  8. tmauldin
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    a12=-33554432

    • one year ago
  9. tmauldin
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    this is how i found it, give me a moment i will explain

    • one year ago
  10. tmauldin
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    since the formula for any term is given by an= a1 *r^(n-1) in order to find any term you must know a1 and r you have a1 but we need to find r, in order to find r we need an and a1 we only have a1 and a6 so substitute a6 for an in the above formula a6=8*r ^(6-1) -8192=8 * r ^(5) -1024=r^5 -4=r now using above formula again we have a12=8 * (-4)^(12-1) a12=8 * (-4)^11 a12=8 * (-4194304) a12=-33554432 hint* any time a term is negative, the ratio will be negative

    • one year ago
  11. tmauldin
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    formula for finding any term in ageometric sequence an=a1*r^(n-1) i have never worked a related problem, so that is why it took so long, but now we both know amistre64 helped me realize you needed a12 good day

    • one year ago
  12. tmauldin
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    geometric equation a.k.a arithmetic transformation

    • one year ago
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