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LyraElizabethAdams
Group Title
PLEASE HELP!!!!
How would you factor: 3x^2 + 2x + 14 = 0
Thanks! :)
 2 years ago
 2 years ago
LyraElizabethAdams Group Title
PLEASE HELP!!!! How would you factor: 3x^2 + 2x + 14 = 0 Thanks! :)
 2 years ago
 2 years ago

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precal Group TitleBest ResponseYou've already chosen the best response.1
You can't factor this but since you set it equal to zero, I believe you meant to say solve it
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.1
dw:1336786604314:dw
 2 years ago

LyraElizabethAdams Group TitleBest ResponseYou've already chosen the best response.1
Oh, okay  I wasn't sure if it could be factored. So, yes  I guess it would be "solve it." Ha, ha  thanks for the correction. :)
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.1
dw:1336786647520:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.1
x=2.519146175 x=1.852479508
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.1
sometimes you can factor a quadratic to solve it, in this case, you can not factor it and therefore it is best to use the quadratic formula remember the decimal solutions are approximations the one I wrote above is an exact solution
 2 years ago

LyraElizabethAdams Group TitleBest ResponseYou've already chosen the best response.1
Wow! Thank you so much, precal! I didn't expect to get such a nice, thorough answer! This really helped. Keep up the great work! =)
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.1
anytime :) I just love to do math and explain it
 2 years ago

LyraElizabethAdams Group TitleBest ResponseYou've already chosen the best response.1
Well, that's certainly a rare gift! I don't know too many people who actually love math. Good for you!
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.1
There are many people at Openstudy who also, have this rare gift. Come back to this site and you will see many of us will help you as the problems get more complicated. I have also, encounter these kind and generous and wise people.
 2 years ago

LyraElizabethAdams Group TitleBest ResponseYou've already chosen the best response.1
Good advice  thanks! I have been using this site, quite frequently, for the past couple of weeks. I LOVE it!
 2 years ago
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