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lanaaa to the rescue :p

which course are u taking lilg/?

you know already ee can you help me?

differentiation?

i think it involves differentiation

this is a differential equation and e^-kt is the homogeneous solution

the value for k (s^-1) is 0.15
the value of t you can say is 1 second

what would it be
-kte^-kt?

0? :s

its really long one minute

Take ur time im not leavin:)

anyone?

do u k anything abt Euler's formula ?

no

e^x=e^z(cosy + i siny)
this is the formula

Jop euler cant be used here:S

http://en.wikipedia.org/wiki/Euler%27s_formula

WHY?

e^2.00(1 second) = cos(1) + 2sin(1)

did it work with u?

that would give me -1.223244275
(btw i made a mistake it should -2sin(1))

so
\[{9.8 \over 2.00} (-1.223244275)\]

but shoudn't it be
\[{9.8^{-2} \over 2.00^{-1}}(-1.223244275)\]

which gives you -0.02547364171

-0.02547364171^-1

is that right?

which is -39.25626384

i think it makes sense
But i'm nt sure

but i also forgot to take in account that 2.00 should 2.00^s-1 :S that confuses me the most

Is your question really just what e is?

http://www.wolframalpha.com/input/?i=y+%3D+10%281+-+e^%28-2t%29%29+from+t%3D0+to+5

where did you get 10 from?
and what about when it says k is measured in s^-1?

ok thanks for that smoothmath

also g = 9.8 ms^-2

{lilg scratches his head}

1) use a spreadsheet to plot the changing velocity over the 0 to 3 seconds for a parachutist

just 9.8 =)

also the end result v is in ms^-1
so the end answer e.g. is 20
would i write it as 20^-1 or just 20

Yup. Don't worry too much about the units here =)

ok :)

use the value of k = 0.15 and t = 1 second

are u asking the value of e? it is approximately equal to 2.71..

Sure.
k = .15 t=1
\[\frac{g}{k}(1-e^{-kt}) = \frac{9.8}{0.15}(1-e^{-0.15*1})\]

Still confused?

do i not use eulers formula then?

when i have e^-0.15*1
what do i do with that?

You don't need to, so I don't see why you should.

\[a^{-x} = (\frac{1}{a})^x\]

so would it be
\[({1 \over e})^{-0.15}\]

Not quite.
\[(\frac{1}{e})^{0.15}\]

oh ok yes my mistake

so it would be
\[(1 - ({1 \over e})^{0.15})\]

Yessir.

thanks alot mate appreciate your great help

My pleasure =)