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mahmit2012 Group Title

solve the problem without calculate x

  • 2 years ago
  • 2 years ago

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  1. mahmit2012 Group Title
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    |dw:1336859839299:dw|

    • 2 years ago
  2. alexwee123 Group Title
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    root n=1-n square both sides n=(1-n)^2 then solve

    • 2 years ago
  3. mahmit2012 Group Title
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    give me the value

    • 2 years ago
  4. alexwee123 Group Title
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    |dw:1336860022459:dw| |dw:1336860159440:dw|

    • 2 years ago
  5. mahmit2012 Group Title
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    please dont calculate x or n...

    • 2 years ago
  6. alexwee123 Group Title
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    one is extraneous :o^^

    • 2 years ago
  7. mahmit2012 Group Title
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    just calculate 2x+xsqx

    • 2 years ago
  8. alexwee123 Group Title
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    oh are these 2 equations linked with each other, like is the value of n for the first equation = n for second? ;o

    • 2 years ago
  9. shashi20008 Group Title
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    from 1st eqn\[x = 1 - \sqrt{x}\] replacing 'x' with this value in \[x \sqrt{x}\] we get\[2x + (1 - \sqrt{x})\sqrt{x}\]\[2x + (\sqrt{x} - x)\]\[x + \sqrt{x} = 1, as per eqn 1.\]

    • 2 years ago
  10. alexwee123 Group Title
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    plug in value of n from first equation then plug it into second

    • 2 years ago
  11. mahmit2012 Group Title
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    i know but that is wrong way please shashi solution

    • 2 years ago
  12. alexwee123 Group Title
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    oh okay :o

    • 2 years ago
  13. Callisto Group Title
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    Don't know if it works... \[x+\sqrt x =1\] \[2x +x\sqrt x\]\[ = 2(1-\sqrt x) + x\sqrt x\]\[ = 2-2\sqrt x + x\sqrt x\]\[ = 2 - \sqrt x( 2- x)\]\[ = 2 - \sqrt x( 2 - (1-\sqrt x))\]\[ = 2 - \sqrt x( 1 +\sqrt x)\]\[ = 2 - \sqrt x - x\]\[=2 - (\sqrt x + x)\]\[=2-1\]\[=1\] Seems I've done something wrong :|

    • 2 years ago
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