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cam330Best ResponseYou've already chosen the best response.0
So are you left with 1/ab^2?
 one year ago

shashi20008Best ResponseYou've already chosen the best response.3
take 'a^3b^2' common in numerator and 'ab' common in denominator.\[a ^{3}b ^{2}(a ^{2}  b ^{2}) / ab(a + b)\]\[a ^{2}b(a b)(a+b)/(a+b)\]\[a ^{2}b(a b)\]\[a ^{3}b  a ^{2}b ^{2}\]
 one year ago

cam330Best ResponseYou've already chosen the best response.0
@ jazy: Then I guess I misread your post. I'm confused, everyone is getting a different answer.
 one year ago

cam330Best ResponseYou've already chosen the best response.0
This is what the problem looks like, if that helps at all.
 one year ago

asnaseerBest ResponseYou've already chosen the best response.0
shashi20008 has given the correct explanation and answer.
 one year ago

jazyBest ResponseYou've already chosen the best response.0
I agree..shashi20008 is right! Sorry about the confusion:(
 one year ago

cam330Best ResponseYou've already chosen the best response.0
That's OK, thanks anyway. :)
 one year ago
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