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cam330
 2 years ago
Best ResponseYou've already chosen the best response.0So are you left with 1/ab^2?

shashi20008
 2 years ago
Best ResponseYou've already chosen the best response.3take 'a^3b^2' common in numerator and 'ab' common in denominator.\[a ^{3}b ^{2}(a ^{2}  b ^{2}) / ab(a + b)\]\[a ^{2}b(a b)(a+b)/(a+b)\]\[a ^{2}b(a b)\]\[a ^{3}b  a ^{2}b ^{2}\]

cam330
 2 years ago
Best ResponseYou've already chosen the best response.0@ jazy: Then I guess I misread your post. I'm confused, everyone is getting a different answer.

cam330
 2 years ago
Best ResponseYou've already chosen the best response.0This is what the problem looks like, if that helps at all.

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.0shashi20008 has given the correct explanation and answer.

jazy
 2 years ago
Best ResponseYou've already chosen the best response.0I agree..shashi20008 is right! Sorry about the confusion:(

cam330
 2 years ago
Best ResponseYou've already chosen the best response.0That's OK, thanks anyway. :)
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