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Simplify (a^5b^2 - a^3b^4)/(a^2b + ab^2)
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Mythias
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a^2b(a-b)
cam330
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How did you get that?
cam330
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So are you left with 1/ab^2?
shashi20008
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take 'a^3b^2' common in numerator and 'ab' common in denominator.\[a ^{3}b ^{2}(a ^{2} - b ^{2}) / ab(a + b)\]\[a ^{2}b(a -b)(a+b)/(a+b)\]\[a ^{2}b(a -b)\]\[a ^{3}b - a ^{2}b ^{2}\]
cam330
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@ jazy: Then I guess I misread your post.
I'm confused, everyone is getting a different answer.
cam330
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|dw:1336862346787:dw|
cam330
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This is what the problem looks like, if that helps at all.
asnaseer
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shashi20008 has given the correct explanation and answer.
jazy
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I agree..shashi20008 is right!
Sorry about the confusion:(
cam330
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That's OK, thanks anyway. :)