A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
Multiply.
(2square root 2)(3 square root 6+1)
Simplify your answer as much as possible.
 2 years ago
Multiply. (2square root 2)(3 square root 6+1) Simplify your answer as much as possible.

This Question is Closed

precal
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1336880574692:dw is this your problem?

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1336880633392:dw

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1336880664057:dw

nightwill
 2 years ago
Best ResponseYou've already chosen the best response.0\[(2\sqrt{2})(3 \sqrt{6}+1)\] \[6\sqrt{6}+23\sqrt{12}\sqrt{2}\] \[6\sqrt{6}+26\sqrt{3}\sqrt{2}\]

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1336880788114:dw

Chiomatn93
 2 years ago
Best ResponseYou've already chosen the best response.0so whats the simplified answer>???? all these numbers and square roots are confusing me!!!

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.0any of the answers are right :/

precal
 2 years ago
Best ResponseYou've already chosen the best response.0the numbers under the square root have to be the same to be considered like terms, since they are not, this is the solution (I put it in a box for you)

nightwill
 2 years ago
Best ResponseYou've already chosen the best response.0It just doesn't look simplified, but it is.

Chiomatn93
 2 years ago
Best ResponseYou've already chosen the best response.0okay thanks so much!
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.