The electric field due to a uniformly charged sphere is maximum at :

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The electric field due to a uniformly charged sphere is maximum at :

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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outer surface..i guess
u guess?
see electric field is indirectly proportional to the square of distance..and at the centre its zero..so id say ki hona to surface pr hi chahiyen..but lemme confirm again

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Other answers:

ok
see this question is a bit incomplete..as the E falls 1/r^2..the maximum strength would lie either inside the sphere or on the surface..it would depend upon the range given to you for the value of R
there r 4 options centre of sphere inside the surface at the surface at infinite distance from the centre
go for inside the surface..the lesser distance the better
ok
once you move out of the sphere the sphere behaves like a point charge.- E=k*q/r2-so r=R at the surface maximum field strength... but if r->infinity then E=0.think so...

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