anonymous
  • anonymous
The electric field due to a uniformly charged sphere is maximum at :
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
outer surface..i guess
anonymous
  • anonymous
u guess?
anonymous
  • anonymous
see electric field is indirectly proportional to the square of distance..and at the centre its zero..so id say ki hona to surface pr hi chahiyen..but lemme confirm again

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anonymous
  • anonymous
ok
anonymous
  • anonymous
see this question is a bit incomplete..as the E falls 1/r^2..the maximum strength would lie either inside the sphere or on the surface..it would depend upon the range given to you for the value of R
anonymous
  • anonymous
there r 4 options centre of sphere inside the surface at the surface at infinite distance from the centre
anonymous
  • anonymous
go for inside the surface..the lesser distance the better
anonymous
  • anonymous
ok
anonymous
  • anonymous
once you move out of the sphere the sphere behaves like a point charge.- E=k*q/r2-so r=R at the surface maximum field strength... but if r->infinity then E=0.think so...

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