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hithere

  • 3 years ago

Evaluate. 7!/4!3! 1 35 210

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  1. ParthKohli
    • 3 years ago
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    \[\Large \color{purple}{\rightarrow {7 * 6 * 5 * 4 * 3 * 2 * 1 \over 4 * 3^2 * 2^2 * 1 } }\]

  2. CeW
    • 3 years ago
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    no need to expand... just use 7! = 7*6*5*4! and cancel out the 4!

  3. ParthKohli
    • 3 years ago
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    Cancel the terms that exist in both numerator and denominator.

  4. ParthKohli
    • 3 years ago
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    I was explaining it in the most basic way.

  5. Callisto
    • 3 years ago
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    \[\frac{7!}{4!3!} = \frac{7\times 6\times 5\times 4!}{4!3!}=\frac{7\times 6\times 5}{3 \times 2 \times 1}\]\[=7 \times 5 =?\]

  6. hithere
    • 3 years ago
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    35

  7. Callisto
    • 3 years ago
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    Yup :)

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