Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Energy levels for an electron in a hydrogen atom are: A. Evenly spaced B. Farther apart near the nucleus C. Closer together near the nucleus D. Arrnaged randomly Please explain.

Chemistry
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

b is correct
But why is so? @gurvinder
energy of nth level is -13.6/(n^2).....calculate difference b/n two adjacent levels...u shudnt have a prob now

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[E=Rhc*1/n^2 \] R, h and c are constant so you can write it as E = 13,6/n^2 but than E is in eV not Joule. n is a natural number (1;2;3;4;5...) If you calculate some energy-levels then you quickly see that the difference in energy gets smaller and smaller for bigger n.

Not the answer you are looking for?

Search for more explanations.

Ask your own question