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find the area of the triangle whose sides have the given lengths.
a=9, b=12, c=15
 one year ago
 one year ago
find the area of the triangle whose sides have the given lengths. a=9, b=12, c=15
 one year ago
 one year ago

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shivam_bhallaBest ResponseYou've already chosen the best response.0
Do you know Heron's formula @Chiomatn93 ? Apply that and you will get your answer
 one year ago

shivam_bhallaBest ResponseYou've already chosen the best response.0
http://en.wikipedia.org/wiki/Heron%27s_formula
 one year ago

ipm1988Best ResponseYou've already chosen the best response.1
\[s= (9+12+15)/2 =18 now by heron's formula Area=\sqrt{18* (189) (1812)(1815)}\] \ [\sqrt{18*9*6*3} = \sqrt{2916} = 54 therefore your area is 54
 one year ago

Chiomatn93Best ResponseYou've already chosen the best response.0
whats the answer and how do u solve?
 one year ago

shivam_bhallaBest ResponseYou've already chosen the best response.0
@Chiomatn93 , Didn't you see the wiki link I gave above ?
 one year ago

Chiomatn93Best ResponseYou've already chosen the best response.0
how do u solve it though? like the steps???
 one year ago

shivam_bhallaBest ResponseYou've already chosen the best response.0
Commo'n the formula is there, the quantities are given. Now can't you multiply and take the square root by yourself
 one year ago

shivam_bhallaBest ResponseYou've already chosen the best response.0
See the formula is \[Area = \sqrt{s(sa)(sb)(sc)}\] where \[s= {a+b+c \over 2}\] where a , b, c are the length of the sides of the triangle. First find s. then substitute to get your Area ??
 one year ago

Chiomatn93Best ResponseYou've already chosen the best response.0
damn calm down...jeez i will do but i just want an example
 one year ago

ipm1988Best ResponseYou've already chosen the best response.1
see my reply solution is there
 one year ago

ipm1988Best ResponseYou've already chosen the best response.1
Ok first you would have to take out the s that is semi perimerter formula for s is S= (a +b +c)/2 here the S is 18 Area of triangle is \[A=\sqrt{s*(sa)*(sb)*(sc)}\] So the area would be now \[A=\sqrt{18*(189)*(1812)*(1815)}\] \[A=\sqrt{18*5*6*3}\] \[A=\sqrt{2916}\] A=54 Therefore the area of triangle is A=54 which is your answer
 one year ago

ipm1988Best ResponseYou've already chosen the best response.1
I cannot put it more simply
 one year ago

Chiomatn93Best ResponseYou've already chosen the best response.0
thank you! i understand it much more now!
 one year ago
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