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Chiomatn93
 3 years ago
find the area of the triangle whose sides have the given lengths.
a=1, b=2, c=2
Chiomatn93
 3 years ago
find the area of the triangle whose sides have the given lengths. a=1, b=2, c=2

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amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1use herons formula, or find an angle with the law of cosine

ipm1988
 3 years ago
Best ResponseYou've already chosen the best response.0@ Chiomatn use the method i gave you it is valid for all

shivam_bhalla
 3 years ago
Best ResponseYou've already chosen the best response.0@Chiomatn93 , I just told you the answer few minutes back. The heron's formula

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1336932257283:dw c^2 = a^2 + b^2 2ab cos(C) c^2a^2b^2  = cos(C) 2ab c^2a^2b^2 cos^1 () = C 2ab 2^2 sinC  = area 2

Chiomatn93
 3 years ago
Best ResponseYou've already chosen the best response.0that wasnt the answer... u just gave me the formula

shivam_bhalla
 3 years ago
Best ResponseYou've already chosen the best response.0@Chiomatn93 , I am not here to give answers :(

shivam_bhalla
 3 years ago
Best ResponseYou've already chosen the best response.0If you want some help , I can help you

Chiomatn93
 3 years ago
Best ResponseYou've already chosen the best response.0all i want is the steps and answer.. i already know the formula.. is s=2.5?

ipm1988
 3 years ago
Best ResponseYou've already chosen the best response.0@ chiomatn93 be confident in what you are you would make mistakes I also did just keep on trying

shivam_bhalla
 3 years ago
Best ResponseYou've already chosen the best response.0@Chiomatn93, you need a calculator, not us :P

eliassaab
 3 years ago
Best ResponseYou've already chosen the best response.2Let \[s =\frac {a+b+c}{2}=\frac 5 2\\ Area= \sqrt{ s(sa)(sb)(sc)}=\frac {\sqrt{15}}{4} \]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1if never been fond of the heron formula :)

eliassaab
 3 years ago
Best ResponseYou've already chosen the best response.2\[ \frac{\sqrt{15}}{4}\approx 0.968246 \]
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