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find the area of the triangle whose sides have the given lengths. a=1, b=2, c=2

Mathematics
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use herons formula, or find an angle with the law of cosine
@ Chiomatn use the method i gave you it is valid for all
is s=2.5?

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Other answers:

@Chiomatn93 , I just told you the answer few minutes back. The heron's formula
|dw:1336932257283:dw| c^2 = a^2 + b^2 -2ab cos(C) c^2-a^2-b^2 ------------ = cos(C) -2ab c^2-a^2-b^2 cos^-1 (------------) = C -2ab 2^2 sinC -------- = area 2
that wasnt the answer... u just gave me the formula
@Chiomatn93 , I am not here to give answers :(
If you want some help , I can help you
all i want is the steps and answer.. i already know the formula.. is s=2.5?
yes
@ chiomatn93 be confident in what you are you would make mistakes I also did just keep on trying
@Chiomatn93, you need a calculator, not us :P
Let \[s =\frac {a+b+c}{2}=\frac 5 2\\ Area= \sqrt{ s(s-a)(s-b)(s-c)}=\frac {\sqrt{15}}{4} \]
if never been fond of the heron formula :)
im getting decimals
\[ \frac{\sqrt{15}}{4}\approx 0.968246 \]

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