Chiomatn93
find the area of the triangle whose sides have the given lengths.
a=1, b=2, c=2



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amistre64
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use herons formula, or find an angle with the law of cosine

ipm1988
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@ Chiomatn use the method i gave you it is valid for all

Chiomatn93
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is s=2.5?

shivam_bhalla
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@Chiomatn93 , I just told you the answer few minutes back. The heron's formula

amistre64
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dw:1336932257283:dw
c^2 = a^2 + b^2 2ab cos(C)
c^2a^2b^2
 = cos(C)
2ab
c^2a^2b^2
cos^1 () = C
2ab
2^2 sinC
 = area
2

Chiomatn93
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that wasnt the answer... u just gave me the formula

shivam_bhalla
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@Chiomatn93 , I am not here to give answers :(

shivam_bhalla
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If you want some help , I can help you

Chiomatn93
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all i want is the steps and answer.. i already know the formula.. is s=2.5?

shivam_bhalla
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yes

ipm1988
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@ chiomatn93 be confident in what you are you would make mistakes I also did just keep on trying

shivam_bhalla
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@Chiomatn93, you need a calculator, not us :P

eliassaab
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Let
\[s =\frac {a+b+c}{2}=\frac 5 2\\
Area= \sqrt{ s(sa)(sb)(sc)}=\frac {\sqrt{15}}{4}
\]

amistre64
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if never been fond of the heron formula :)

Chiomatn93
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im getting decimals

eliassaab
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\[
\frac{\sqrt{15}}{4}\approx 0.968246
\]