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Chiomatn93

  • 2 years ago

find the area of the triangle whose sides have the given lengths. a=1, b=2, c=2

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  1. amistre64
    • 2 years ago
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    use herons formula, or find an angle with the law of cosine

  2. ipm1988
    • 2 years ago
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    @ Chiomatn use the method i gave you it is valid for all

  3. Chiomatn93
    • 2 years ago
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    is s=2.5?

  4. shivam_bhalla
    • 2 years ago
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    @Chiomatn93 , I just told you the answer few minutes back. The heron's formula

  5. amistre64
    • 2 years ago
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    |dw:1336932257283:dw| c^2 = a^2 + b^2 -2ab cos(C) c^2-a^2-b^2 ------------ = cos(C) -2ab c^2-a^2-b^2 cos^-1 (------------) = C -2ab 2^2 sinC -------- = area 2

  6. Chiomatn93
    • 2 years ago
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    that wasnt the answer... u just gave me the formula

  7. shivam_bhalla
    • 2 years ago
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    @Chiomatn93 , I am not here to give answers :(

  8. shivam_bhalla
    • 2 years ago
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    If you want some help , I can help you

  9. Chiomatn93
    • 2 years ago
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    all i want is the steps and answer.. i already know the formula.. is s=2.5?

  10. shivam_bhalla
    • 2 years ago
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    yes

  11. ipm1988
    • 2 years ago
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    @ chiomatn93 be confident in what you are you would make mistakes I also did just keep on trying

  12. shivam_bhalla
    • 2 years ago
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    @Chiomatn93, you need a calculator, not us :P

  13. eliassaab
    • 2 years ago
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    Let \[s =\frac {a+b+c}{2}=\frac 5 2\\ Area= \sqrt{ s(s-a)(s-b)(s-c)}=\frac {\sqrt{15}}{4} \]

  14. amistre64
    • 2 years ago
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    if never been fond of the heron formula :)

  15. Chiomatn93
    • 2 years ago
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    im getting decimals

  16. eliassaab
    • 2 years ago
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    \[ \frac{\sqrt{15}}{4}\approx 0.968246 \]

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