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krissywatts

  • 3 years ago

use a system of equations in two variables solve the following problem: 4 times a first number decreased by 3 times a second number is 22. The sum between the first number and twice the second number is 0. Find the number?

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  1. jazy
    • 3 years ago
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    first number = x second number = y so you have the equations: 4x - 3y = 22 x + 2y = 0

  2. jazy
    • 3 years ago
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    Which number is it asking you to find? The first or the second?

  3. krissywatts
    • 3 years ago
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    I have to get numbers for both

  4. jazy
    • 3 years ago
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    Ok then lets solve for x first: 4x - 3y = 22 +3y 4x = 22 + 3y /4 x = 5.5 + 0.75y Now substitute the value of x into the second equation: x + 2y = 0 (5.5 + 0.75y) + 2y = 0 Now you combine the like terms: 5.5 + 0.75y + 2y = 0

  5. jazy
    • 3 years ago
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    When you combine 5.5 + 0.75y + 2y = 0 you'll get the value of y.

  6. jazy
    • 3 years ago
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    So what do you get when you solve fore y in: 5.5 + 0.75y + 2y = 0

  7. krissywatts
    • 3 years ago
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    I get -2

  8. krissywatts
    • 3 years ago
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    and for x i get 4 is this all correct?

  9. krissywatts
    • 3 years ago
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    Thanks you if so.

  10. jazy
    • 3 years ago
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    Yep your're right!:D No problem:)

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