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dpaIncBest ResponseYou've already chosen the best response.3
for the first one, u=cosx
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
this doesnt seem like a usub problem @dpaInc looks like that basic application of general power formula
 one year ago

RomeroBest ResponseYou've already chosen the best response.0
@lgbasallote Not for the first one
 one year ago

dpaIncBest ResponseYou've already chosen the best response.3
not necessarily but i like to do it so I don't miss the derivative of 23t...
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
me too...that formula is too confusing :/ kinda like doing limits to find derivative
 one year ago

dpaIncBest ResponseYou've already chosen the best response.3
and @Romero , yes there's more than one way to skin this cat.. for the first one, the integrand can be rewritten as secxtanx
 one year ago

wendoBest ResponseYou've already chosen the best response.0
from my caculation first one is 1/cosx+c second one is (23t)^7/21 +c is that right
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i think there should be a negative on #1
 one year ago

campbell_stBest ResponseYou've already chosen the best response.0
looks like a nice simple substitution to me... but I'm still waiting for the rooster eggs to roll off the roof
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
#2 seems right though @campbell_st whatis it with you and eggs :p
 one year ago

RomeroBest ResponseYou've already chosen the best response.0
Second one is right. You just wrote it weird so it looks like the ^7 is getting divided by 21
 one year ago

RomeroBest ResponseYou've already chosen the best response.0
derivative of cos will give you a negative so when you do the chain rule you will need to cancel that negative with another one.
 one year ago

quarkineBest ResponseYou've already chosen the best response.0
these are too basic...perhaps u need to revisit the integration methods... 1/cosx and ((23t)^7)/(3*7)
 one year ago

frecklesBest ResponseYou've already chosen the best response.1
\[\int\limits_{}^{}\frac{\sin(x)}{(\cos(x))^2} dx ...u=\cos(x) =>du=\sin(x) dx ......\int\limits_{}^{}\frac{du}{u^2}=\int\limits_{}^{}u^{2} du\] \[\int\limits_{}^{}(23t)^6 dt....u=23t=> du=3 dt .....\int\limits_{}^{}u^6 \frac{du}{3}\]
 one year ago

.Sam.Best ResponseYou've already chosen the best response.0
#2 \[\int\limits (23 t)^6 \, dt\] u==23t, du=3dt \[\frac{1}{3}\int\limits u^6 \, du\] \[\frac{u^7}{21}+c\] \[\frac{(23 t)^7}{21} +c\]
 one year ago
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