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anonymous
 4 years ago
cosec x= 1/2 (x)+1
has root 0<x<1/2 pi
verify by calculation that this root lies between 0.5 and 1
anonymous
 4 years ago
cosec x= 1/2 (x)+1 has root 0<x<1/2 pi verify by calculation that this root lies between 0.5 and 1

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Remember 1 <= sin x <= 1 Therefore 1 <= cosec x <=1 Now try :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0One more question. This is your question , right \[cosec x= {1 \over 2 }(x)+1\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OK. Just put instead of cosec x , 1/2(x) +1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok @NotSObright , let's see what you have done :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Say y1=1/2x+1 y2=csc(x) y1(0)=1 y1(Pi/2)=Pi/4+1 y2(0)=infinty y2(Pi/2)=1 Since it can be proven using differentiation y1 is inceasing and y2 is decreasing on 0,pi/2 hence in order to attain boundary values graphs must cross each other

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So what about the 0.5 and 1?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry i didn't see that u must show at 0.5 y1<y2 and at 1 y1>y2 u might wanna use a calculator

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1336990897568:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is in calculation u need to calculate values at o.5 and 1 to show the inequality

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have told everything u need go through the conversation and try to use ur intelligence
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