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cosec x= 1/2 (x)+1
has root 0<x<1/2 pi
verify by calculation that this root lies between 0.5 and 1
 one year ago
 one year ago
cosec x= 1/2 (x)+1 has root 0<x<1/2 pi verify by calculation that this root lies between 0.5 and 1
 one year ago
 one year ago

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shivam_bhallaBest ResponseYou've already chosen the best response.0
Remember 1 <= sin x <= 1 Therefore 1 <= cosec x <=1 Now try :)
 one year ago

shivam_bhallaBest ResponseYou've already chosen the best response.0
One more question. This is your question , right \[cosec x= {1 \over 2 }(x)+1\]
 one year ago

NotSObrightBest ResponseYou've already chosen the best response.1
I think i solved it
 one year ago

shivam_bhallaBest ResponseYou've already chosen the best response.0
OK. Just put instead of cosec x , 1/2(x) +1
 one year ago

shivam_bhallaBest ResponseYou've already chosen the best response.0
Ok @NotSObright , let's see what you have done :P
 one year ago

NotSObrightBest ResponseYou've already chosen the best response.1
Say y1=1/2x+1 y2=csc(x) y1(0)=1 y1(Pi/2)=Pi/4+1 y2(0)=infinty y2(Pi/2)=1 Since it can be proven using differentiation y1 is inceasing and y2 is decreasing on 0,pi/2 hence in order to attain boundary values graphs must cross each other
 one year ago

orderBest ResponseYou've already chosen the best response.0
So what about the 0.5 and 1?
 one year ago

NotSObrightBest ResponseYou've already chosen the best response.1
sorry i didn't see that u must show at 0.5 y1<y2 and at 1 y1>y2 u might wanna use a calculator
 one year ago

NotSObrightBest ResponseYou've already chosen the best response.1
dw:1336990897568:dw
 one year ago

NotSObrightBest ResponseYou've already chosen the best response.1
it is in calculation u need to calculate values at o.5 and 1 to show the inequality
 one year ago

NotSObrightBest ResponseYou've already chosen the best response.1
i have told everything u need go through the conversation and try to use ur intelligence
 one year ago
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