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See
\[{GM_e M_o \over R_e +h}= {1 \over 2} m_o v^2\]

M_e --> Mass of earth
R_e -->Radius of Eart
M_o-->Mass of projectile
v-->escape velocity

The above equation is by energy conservation

:D

R---> Radius of earth
h--> height of projectile from earth

Okay you mean you want a 'feel'? Hmm. Okay.

shiv what is buddhi lagao ?

"Use your brains " :P

mean use ur brain grrrrrrr.........

buddhi lagao ---> translates to --> apply brains

*sic

Main bhi popat bane ke bad sikha ye concept. So don't worry :D

ye concept *sikha

but one thing surely i m not going to forgot this concept ever :P

*derive

Sorry not *free exactly but if you want help in any specific derivation, then I can help you

*to

LOL np :)

ok byee...

shiv are u there?

how the angle inpnd?

inpnd??

am asking why the angle is independ of the escape velocity?

*putting

@shivam_bhalla putting?

thanks then what is the angle of that minimum velocity? @shivam_bhalla

Ofcourse, 90 degrees

you assume space is spherical yeah?

The gravitational force of the the earth acts spherically as a function of r.

thanks yar bye

bye

he is having trouble in posting answer.. :(