why the escape velocity is independent of mass of projecting object and angle of projection?

- anonymous

why the escape velocity is independent of mass of projecting object and angle of projection?

- katieb

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- anonymous

@Callisto @Mani_Jha @apoorvk @Diyadiya @shivam_bhalla

- anonymous

See
\[{GM_e M_o \over R_e +h}= {1 \over 2} m_o v^2\]

- anonymous

M_e --> Mass of earth
R_e -->Radius of Eart
M_o-->Mass of projectile
v-->escape velocity

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## More answers

- anonymous

The above equation is by energy conservation

- apoorvk

buddhi lagao.
Energy concept. the potential barrier has to be crossed. apply shivam's equation above.

- anonymous

So M_o cancels and as @apoorvk said, buddhi lagao :P

- apoorvk

:D

- anonymous

lol.. anyways i need a theoretical ans if u guys see the formulae there is a presence of mass isntd ?? which show it dependent on mass right?

- anonymous

R---> Radius of earth
h--> height of projectile from earth

- anonymous

@heena , "Open your eyes" It shows dependence on "MASS OF THE EARTH"

- apoorvk

Okay you mean you want a 'feel'? Hmm. Okay.

- anonymous

shiv what is buddhi lagao ?

- anonymous

"Use your brains " :P

- anonymous

mean use ur brain grrrrrrr.........

- apoorvk

buddhi lagao ---> translates to --> apply brains

- apoorvk

*sic

- anonymous

@heena , aur kuch (anything else ) ??

- anonymous

ok means it is depends on mass but mass of earth right :) thnk you all of u meri khinchai krne k liye :P popat kr diya mera hur. :D

- anonymous

Main bhi popat bane ke bad sikha ye concept. So don't worry :D

- anonymous

ye concept *sikha

- anonymous

janti hu par guys y qn mera ni tha :P some one asked or m physc m apna dimag ni lagati sirf fimrulae se mtlb rakhti hu :P baki to aplog ho na :D :D

- anonymous

but one thing surely i m not going to forgot this concept ever :P

- anonymous

LOL Remember only the vital Formulas and derice the rest using conservation of
1) Energy
2)linear momentum
3)Angular momentum

- anonymous

*derive

- anonymous

bhalla u free?? mje isme se ek bhi derivation ni ati frnkly sayin i m so dumb plz help me if u have time tell me how we do derivation :?

- anonymous

Sorry not *free exactly but if you want help in any specific derivation, then I can help you

- anonymous

actaully in 11 my teacher dosent teach v.well thi topic i mean conservation of laws dats y i m facing problems.. :(

- anonymous

Go through the basics of work , gravitational force, kinetic energy, linear momentum, angular momentum, Then for any derivation,you have to apply only these 2 or 3 laws
conservation of
1) Energy
2)linear momentum
3)Angular momentum
If you have any doubt, you can post a question here and tag me. I will try t help you with that derivation

- anonymous

*to

- anonymous

ok thnk you guys for being here i have to go to study and yea i ll shivam and one qn @shivam yeterday was ur bday?

- anonymous

or @apoorvk

- anonymous

@heena , yes

- anonymous

dw m yaha sbko tang krne k liye hi hu :D :D
and belated bday sorry unable to find u yeterday...
many many returns of the belated day... and orry once again for being late to wish u...

- anonymous

LOL np :)

- anonymous

ok byee...

- anonymous

shiv are u there?

- anonymous

yes @swalah

- anonymous

how the angle inpnd?

- anonymous

inpnd??

- anonymous

am asking why the angle is independ of the escape velocity?

- anonymous

LOL, Ofcourse @swalah , put an angle of projection will increase your escape velocity and escape velocity is the "minimum" velocity required to escape the gravity of earth

- anonymous

*putting

- anonymous

@shivam_bhalla putting?

- anonymous

LOL, Ofcourse @swalah , "putting " an angle of projection will increase your escape velocity and escape velocity is the "minimum" velocity required to escape the gravity of earth

- anonymous

thanks then what is the angle of that minimum velocity? @shivam_bhalla

- anonymous

Ofcourse, 90 degrees

- anonymous

you assume space is spherical yeah?

- anonymous

@shivam_bhalla

- anonymous

The gravitational force of the the earth acts spherically as a function of r.

- anonymous

thanks yar bye

- anonymous

bye

- anonymous

from behalf of @Mani_Jha
It doesn't matter whether you throw a bus or a ball into space. Both of them need the same speed 11.6 km/sec to do that(escape velocity of earth). A possible reason of that is that the gravitational field(g) is same for all objects on earth. All objects are in the same field(gravitational) and so require the same velocity to escape the earth. Also, whatever the object be, it has to travel the same distance from the ground to space. Although, it is more difficult to give a bus a speed of 11.6 km/sec than to a ball. Whether you throw it vertically upwards or at an angle, it doesn't matter for the speed. This is because, as shivam_bhalla said, the earth is spherically symmetrical(roughly). Look above at the sky. There is space everywhere at the same distance from you. So, from wherever you throw it, if it has a speed of 11.6 km/sec, it will reach space. , as I think that @shivam_bhalla might have been mistaken.

- anonymous

@heena ,
You are right. :D I was half sleepy . thanks for correcting me. :)

- anonymous

no give thanks to @Mani_Jha as i mention in behalf of him i m posting the answer..

- anonymous

he is having trouble in posting answer.. :(

- anonymous

Thanks @Mani_Jha . and @heena , I was just about to ask about that

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