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heena Group Title

why the escape velocity is independent of mass of projecting object and angle of projection?

  • 2 years ago
  • 2 years ago

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  1. heena Group Title
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    @Callisto @Mani_Jha @apoorvk @Diyadiya @shivam_bhalla

    • 2 years ago
  2. shivam_bhalla Group Title
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    See \[{GM_e M_o \over R_e +h}= {1 \over 2} m_o v^2\]

    • 2 years ago
  3. shivam_bhalla Group Title
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    M_e --> Mass of earth R_e -->Radius of Eart M_o-->Mass of projectile v-->escape velocity

    • 2 years ago
  4. shivam_bhalla Group Title
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    The above equation is by energy conservation

    • 2 years ago
  5. apoorvk Group Title
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    buddhi lagao. Energy concept. the potential barrier has to be crossed. apply shivam's equation above.

    • 2 years ago
  6. shivam_bhalla Group Title
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    So M_o cancels and as @apoorvk said, buddhi lagao :P

    • 2 years ago
  7. apoorvk Group Title
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    :D

    • 2 years ago
  8. heena Group Title
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    lol.. anyways i need a theoretical ans if u guys see the formulae there is a presence of mass isntd ?? which show it dependent on mass right?

    • 2 years ago
  9. shivam_bhalla Group Title
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    R---> Radius of earth h--> height of projectile from earth

    • 2 years ago
  10. shivam_bhalla Group Title
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    @heena , "Open your eyes" It shows dependence on "MASS OF THE EARTH"

    • 2 years ago
  11. apoorvk Group Title
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    Okay you mean you want a 'feel'? Hmm. Okay.

    • 2 years ago
  12. swalah Group Title
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    shiv what is buddhi lagao ?

    • 2 years ago
  13. shivam_bhalla Group Title
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    "Use your brains " :P

    • 2 years ago
  14. heena Group Title
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    mean use ur brain grrrrrrr.........

    • 2 years ago
  15. apoorvk Group Title
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    buddhi lagao ---> translates to --> apply brains

    • 2 years ago
  16. apoorvk Group Title
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    *sic

    • 2 years ago
  17. shivam_bhalla Group Title
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    @heena , aur kuch (anything else ) ??

    • 2 years ago
  18. heena Group Title
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    ok means it is depends on mass but mass of earth right :) thnk you all of u meri khinchai krne k liye :P popat kr diya mera hur. :D

    • 2 years ago
  19. shivam_bhalla Group Title
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    Main bhi popat bane ke bad sikha ye concept. So don't worry :D

    • 2 years ago
  20. shivam_bhalla Group Title
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    ye concept *sikha

    • 2 years ago
  21. heena Group Title
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    janti hu par guys y qn mera ni tha :P some one asked or m physc m apna dimag ni lagati sirf fimrulae se mtlb rakhti hu :P baki to aplog ho na :D :D

    • 2 years ago
  22. heena Group Title
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    but one thing surely i m not going to forgot this concept ever :P

    • 2 years ago
  23. shivam_bhalla Group Title
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    LOL Remember only the vital Formulas and derice the rest using conservation of 1) Energy 2)linear momentum 3)Angular momentum

    • 2 years ago
  24. shivam_bhalla Group Title
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    *derive

    • 2 years ago
  25. heena Group Title
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    bhalla u free?? mje isme se ek bhi derivation ni ati frnkly sayin i m so dumb plz help me if u have time tell me how we do derivation :?

    • 2 years ago
  26. shivam_bhalla Group Title
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    Sorry not *free exactly but if you want help in any specific derivation, then I can help you

    • 2 years ago
  27. heena Group Title
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    actaully in 11 my teacher dosent teach v.well thi topic i mean conservation of laws dats y i m facing problems.. :(

    • 2 years ago
  28. shivam_bhalla Group Title
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    Go through the basics of work , gravitational force, kinetic energy, linear momentum, angular momentum, Then for any derivation,you have to apply only these 2 or 3 laws conservation of 1) Energy 2)linear momentum 3)Angular momentum If you have any doubt, you can post a question here and tag me. I will try t help you with that derivation

    • 2 years ago
  29. shivam_bhalla Group Title
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    *to

    • 2 years ago
  30. heena Group Title
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    ok thnk you guys for being here i have to go to study and yea i ll shivam and one qn @shivam yeterday was ur bday?

    • 2 years ago
  31. shivam_bhalla Group Title
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    or @apoorvk

    • 2 years ago
  32. shivam_bhalla Group Title
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    @heena , yes

    • 2 years ago
  33. heena Group Title
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    dw m yaha sbko tang krne k liye hi hu :D :D and belated bday sorry unable to find u yeterday... many many returns of the belated day... and orry once again for being late to wish u...

    • 2 years ago
  34. shivam_bhalla Group Title
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    LOL np :)

    • 2 years ago
  35. heena Group Title
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    ok byee...

    • 2 years ago
  36. swalah Group Title
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    shiv are u there?

    • 2 years ago
  37. shivam_bhalla Group Title
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    yes @swalah

    • 2 years ago
  38. swalah Group Title
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    how the angle inpnd?

    • 2 years ago
  39. shivam_bhalla Group Title
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    inpnd??

    • 2 years ago
  40. swalah Group Title
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    am asking why the angle is independ of the escape velocity?

    • 2 years ago
  41. shivam_bhalla Group Title
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    LOL, Ofcourse @swalah , put an angle of projection will increase your escape velocity and escape velocity is the "minimum" velocity required to escape the gravity of earth

    • 2 years ago
  42. shivam_bhalla Group Title
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    *putting

    • 2 years ago
  43. swalah Group Title
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    @shivam_bhalla putting?

    • 2 years ago
  44. shivam_bhalla Group Title
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    LOL, Ofcourse @swalah , "putting " an angle of projection will increase your escape velocity and escape velocity is the "minimum" velocity required to escape the gravity of earth

    • 2 years ago
  45. swalah Group Title
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    thanks then what is the angle of that minimum velocity? @shivam_bhalla

    • 2 years ago
  46. shivam_bhalla Group Title
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    Ofcourse, 90 degrees

    • 2 years ago
  47. swalah Group Title
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    you assume space is spherical yeah?

    • 2 years ago
  48. swalah Group Title
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    @shivam_bhalla

    • 2 years ago
  49. shivam_bhalla Group Title
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    The gravitational force of the the earth acts spherically as a function of r.

    • 2 years ago
  50. swalah Group Title
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    thanks yar bye

    • 2 years ago
  51. shivam_bhalla Group Title
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    bye

    • 2 years ago
  52. heena Group Title
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    from behalf of @Mani_Jha It doesn't matter whether you throw a bus or a ball into space. Both of them need the same speed 11.6 km/sec to do that(escape velocity of earth). A possible reason of that is that the gravitational field(g) is same for all objects on earth. All objects are in the same field(gravitational) and so require the same velocity to escape the earth. Also, whatever the object be, it has to travel the same distance from the ground to space. Although, it is more difficult to give a bus a speed of 11.6 km/sec than to a ball. Whether you throw it vertically upwards or at an angle, it doesn't matter for the speed. This is because, as shivam_bhalla said, the earth is spherically symmetrical(roughly). Look above at the sky. There is space everywhere at the same distance from you. So, from wherever you throw it, if it has a speed of 11.6 km/sec, it will reach space. , as I think that @shivam_bhalla might have been mistaken.

    • 2 years ago
  53. shivam_bhalla Group Title
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    @heena , You are right. :D I was half sleepy . thanks for correcting me. :)

    • 2 years ago
  54. heena Group Title
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    no give thanks to @Mani_Jha as i mention in behalf of him i m posting the answer..

    • 2 years ago
  55. heena Group Title
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    he is having trouble in posting answer.. :(

    • 2 years ago
  56. shivam_bhalla Group Title
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    Thanks @Mani_Jha . and @heena , I was just about to ask about that

    • 2 years ago
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