Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

heena

why the escape velocity is independent of mass of projecting object and angle of projection?

  • one year ago
  • one year ago

  • This Question is Closed
  1. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    @Callisto @Mani_Jha @apoorvk @Diyadiya @shivam_bhalla

    • one year ago
  2. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    See \[{GM_e M_o \over R_e +h}= {1 \over 2} m_o v^2\]

    • one year ago
  3. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    M_e --> Mass of earth R_e -->Radius of Eart M_o-->Mass of projectile v-->escape velocity

    • one year ago
  4. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    The above equation is by energy conservation

    • one year ago
  5. apoorvk
    Best Response
    You've already chosen the best response.
    Medals 0

    buddhi lagao. Energy concept. the potential barrier has to be crossed. apply shivam's equation above.

    • one year ago
  6. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    So M_o cancels and as @apoorvk said, buddhi lagao :P

    • one year ago
  7. apoorvk
    Best Response
    You've already chosen the best response.
    Medals 0

    :D

    • one year ago
  8. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    lol.. anyways i need a theoretical ans if u guys see the formulae there is a presence of mass isntd ?? which show it dependent on mass right?

    • one year ago
  9. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    R---> Radius of earth h--> height of projectile from earth

    • one year ago
  10. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    @heena , "Open your eyes" It shows dependence on "MASS OF THE EARTH"

    • one year ago
  11. apoorvk
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay you mean you want a 'feel'? Hmm. Okay.

    • one year ago
  12. swalah
    Best Response
    You've already chosen the best response.
    Medals 0

    shiv what is buddhi lagao ?

    • one year ago
  13. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    "Use your brains " :P

    • one year ago
  14. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    mean use ur brain grrrrrrr.........

    • one year ago
  15. apoorvk
    Best Response
    You've already chosen the best response.
    Medals 0

    buddhi lagao ---> translates to --> apply brains

    • one year ago
  16. apoorvk
    Best Response
    You've already chosen the best response.
    Medals 0

    *sic

    • one year ago
  17. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    @heena , aur kuch (anything else ) ??

    • one year ago
  18. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    ok means it is depends on mass but mass of earth right :) thnk you all of u meri khinchai krne k liye :P popat kr diya mera hur. :D

    • one year ago
  19. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    Main bhi popat bane ke bad sikha ye concept. So don't worry :D

    • one year ago
  20. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    ye concept *sikha

    • one year ago
  21. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    janti hu par guys y qn mera ni tha :P some one asked or m physc m apna dimag ni lagati sirf fimrulae se mtlb rakhti hu :P baki to aplog ho na :D :D

    • one year ago
  22. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    but one thing surely i m not going to forgot this concept ever :P

    • one year ago
  23. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    LOL Remember only the vital Formulas and derice the rest using conservation of 1) Energy 2)linear momentum 3)Angular momentum

    • one year ago
  24. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    *derive

    • one year ago
  25. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    bhalla u free?? mje isme se ek bhi derivation ni ati frnkly sayin i m so dumb plz help me if u have time tell me how we do derivation :?

    • one year ago
  26. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    Sorry not *free exactly but if you want help in any specific derivation, then I can help you

    • one year ago
  27. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    actaully in 11 my teacher dosent teach v.well thi topic i mean conservation of laws dats y i m facing problems.. :(

    • one year ago
  28. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    Go through the basics of work , gravitational force, kinetic energy, linear momentum, angular momentum, Then for any derivation,you have to apply only these 2 or 3 laws conservation of 1) Energy 2)linear momentum 3)Angular momentum If you have any doubt, you can post a question here and tag me. I will try t help you with that derivation

    • one year ago
  29. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    *to

    • one year ago
  30. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    ok thnk you guys for being here i have to go to study and yea i ll shivam and one qn @shivam yeterday was ur bday?

    • one year ago
  31. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    or @apoorvk

    • one year ago
  32. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    @heena , yes

    • one year ago
  33. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    dw m yaha sbko tang krne k liye hi hu :D :D and belated bday sorry unable to find u yeterday... many many returns of the belated day... and orry once again for being late to wish u...

    • one year ago
  34. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    LOL np :)

    • one year ago
  35. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    ok byee...

    • one year ago
  36. swalah
    Best Response
    You've already chosen the best response.
    Medals 0

    shiv are u there?

    • one year ago
  37. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    yes @swalah

    • one year ago
  38. swalah
    Best Response
    You've already chosen the best response.
    Medals 0

    how the angle inpnd?

    • one year ago
  39. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    inpnd??

    • one year ago
  40. swalah
    Best Response
    You've already chosen the best response.
    Medals 0

    am asking why the angle is independ of the escape velocity?

    • one year ago
  41. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    LOL, Ofcourse @swalah , put an angle of projection will increase your escape velocity and escape velocity is the "minimum" velocity required to escape the gravity of earth

    • one year ago
  42. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    *putting

    • one year ago
  43. swalah
    Best Response
    You've already chosen the best response.
    Medals 0

    @shivam_bhalla putting?

    • one year ago
  44. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    LOL, Ofcourse @swalah , "putting " an angle of projection will increase your escape velocity and escape velocity is the "minimum" velocity required to escape the gravity of earth

    • one year ago
  45. swalah
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks then what is the angle of that minimum velocity? @shivam_bhalla

    • one year ago
  46. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    Ofcourse, 90 degrees

    • one year ago
  47. swalah
    Best Response
    You've already chosen the best response.
    Medals 0

    you assume space is spherical yeah?

    • one year ago
  48. swalah
    Best Response
    You've already chosen the best response.
    Medals 0

    @shivam_bhalla

    • one year ago
  49. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    The gravitational force of the the earth acts spherically as a function of r.

    • one year ago
  50. swalah
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks yar bye

    • one year ago
  51. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    bye

    • one year ago
  52. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    from behalf of @Mani_Jha It doesn't matter whether you throw a bus or a ball into space. Both of them need the same speed 11.6 km/sec to do that(escape velocity of earth). A possible reason of that is that the gravitational field(g) is same for all objects on earth. All objects are in the same field(gravitational) and so require the same velocity to escape the earth. Also, whatever the object be, it has to travel the same distance from the ground to space. Although, it is more difficult to give a bus a speed of 11.6 km/sec than to a ball. Whether you throw it vertically upwards or at an angle, it doesn't matter for the speed. This is because, as shivam_bhalla said, the earth is spherically symmetrical(roughly). Look above at the sky. There is space everywhere at the same distance from you. So, from wherever you throw it, if it has a speed of 11.6 km/sec, it will reach space. , as I think that @shivam_bhalla might have been mistaken.

    • one year ago
  53. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    @heena , You are right. :D I was half sleepy . thanks for correcting me. :)

    • one year ago
  54. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    no give thanks to @Mani_Jha as i mention in behalf of him i m posting the answer..

    • one year ago
  55. heena
    Best Response
    You've already chosen the best response.
    Medals 3

    he is having trouble in posting answer.. :(

    • one year ago
  56. shivam_bhalla
    Best Response
    You've already chosen the best response.
    Medals 3

    Thanks @Mani_Jha . and @heena , I was just about to ask about that

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.