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is it okay to do this...? and did i get it correct anyway? the third term of an exponential sequence is 12 and the 9th term is 768. find the values of the common ratio.
\[\large ar^2=12 \]\[\large ar^8=768\]
\[\large \frac{ar^8}{ar^2}=\frac{768}{12}\]
\[\large r^6=64 \]
\[\large r=2 \ , \ r=2\]
I forgot the formulas and decided to go with this but i don't know if it is correct or even if it's acceptable... can anyone confirm for me please?
 one year ago
 one year ago
is it okay to do this...? and did i get it correct anyway? the third term of an exponential sequence is 12 and the 9th term is 768. find the values of the common ratio. \[\large ar^2=12 \]\[\large ar^8=768\] \[\large \frac{ar^8}{ar^2}=\frac{768}{12}\] \[\large r^6=64 \] \[\large r=2 \ , \ r=2\] I forgot the formulas and decided to go with this but i don't know if it is correct or even if it's acceptable... can anyone confirm for me please?
 one year ago
 one year ago

This Question is Closed

sasogeekBest ResponseYou've already chosen the best response.0
truth is i've even forgotten if this is exactly how to do it lol. i literally have no memory of the classes i took for this topic
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
You are perfectly correct, math can be done in infinite ways :)
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.0
it looks like a geometric progression.. i dont know what's an exponential sequence.. http://en.wikipedia.org/wiki/Exponential_sheaf_sequence
 one year ago

.Sam.Best ResponseYou've already chosen the best response.3
\[a_3=12\] \[a_9=768\]  \[ar^2=12\] \[ar^8=768\] \[\frac{12}{r^2}r^8=768\] \[r^6=64\] \[r= \pm 2\]
 one year ago

sasogeekBest ResponseYou've already chosen the best response.0
same thing :) different name
 one year ago

.Sam.Best ResponseYou've already chosen the best response.3
GP formula \[\Huge T_n=a_1r^{n1}\]
 one year ago
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