## sasogeek Group Title is it okay to do this...? and did i get it correct anyway? the third term of an exponential sequence is 12 and the 9th term is 768. find the values of the common ratio. $\large ar^2=12$$\large ar^8=768$ $\large \frac{ar^8}{ar^2}=\frac{768}{12}$ $\large r^6=64$ $\large r=2 \ , \ r=-2$ I forgot the formulas and decided to go with this but i don't know if it is correct or even if it's acceptable... can anyone confirm for me please? 2 years ago 2 years ago

1. sasogeek

truth is i've even forgotten if this is exactly how to do it lol. i literally have no memory of the classes i took for this topic

2. .Sam.

yeah you can do that

3. ParthKohli

You are perfectly correct, math can be done in infinite ways :)

4. Mimi_x3

it looks like a geometric progression.. i dont know what's an exponential sequence.. http://en.wikipedia.org/wiki/Exponential_sheaf_sequence

5. .Sam.

$a_3=12$ $a_9=768$ ------------- $ar^2=12$ $ar^8=768$ $\frac{12}{r^2}r^8=768$ $r^6=64$ $r= \pm 2$

6. sasogeek

same thing :) different name

7. .Sam.

GP formula $\Huge T_n=a_1r^{n-1}$

8. sasogeek

thanks :)

9. .Sam.

np