Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

is it okay to do this...? and did i get it correct anyway? the third term of an exponential sequence is 12 and the 9th term is 768. find the values of the common ratio. \[\large ar^2=12 \]\[\large ar^8=768\] \[\large \frac{ar^8}{ar^2}=\frac{768}{12}\] \[\large r^6=64 \] \[\large r=2 \ , \ r=-2\] I forgot the formulas and decided to go with this but i don't know if it is correct or even if it's acceptable... can anyone confirm for me please?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

truth is i've even forgotten if this is exactly how to do it lol. i literally have no memory of the classes i took for this topic
yeah you can do that
You are perfectly correct, math can be done in infinite ways :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

it looks like a geometric progression.. i dont know what's an exponential sequence.. http://en.wikipedia.org/wiki/Exponential_sheaf_sequence
\[a_3=12\] \[a_9=768\] ------------- \[ar^2=12\] \[ar^8=768\] \[\frac{12}{r^2}r^8=768\] \[r^6=64\] \[r= \pm 2\]
same thing :) different name
GP formula \[\Huge T_n=a_1r^{n-1}\]
thanks :)
np

Not the answer you are looking for?

Search for more explanations.

Ask your own question