sasogeek 3 years ago is it okay to do this...? and did i get it correct anyway? the third term of an exponential sequence is 12 and the 9th term is 768. find the values of the common ratio. $\large ar^2=12$$\large ar^8=768$ $\large \frac{ar^8}{ar^2}=\frac{768}{12}$ $\large r^6=64$ $\large r=2 \ , \ r=-2$ I forgot the formulas and decided to go with this but i don't know if it is correct or even if it's acceptable... can anyone confirm for me please?

1. sasogeek

truth is i've even forgotten if this is exactly how to do it lol. i literally have no memory of the classes i took for this topic

2. .Sam.

yeah you can do that

3. ParthKohli

You are perfectly correct, math can be done in infinite ways :)

4. Mimi_x3

it looks like a geometric progression.. i dont know what's an exponential sequence.. http://en.wikipedia.org/wiki/Exponential_sheaf_sequence

5. .Sam.

$a_3=12$ $a_9=768$ ------------- $ar^2=12$ $ar^8=768$ $\frac{12}{r^2}r^8=768$ $r^6=64$ $r= \pm 2$

6. sasogeek

same thing :) different name

7. .Sam.

GP formula $\Huge T_n=a_1r^{n-1}$

8. sasogeek

thanks :)

9. .Sam.

np