• sasogeek
is it okay to do this...? and did i get it correct anyway? the third term of an exponential sequence is 12 and the 9th term is 768. find the values of the common ratio. $\large ar^2=12$$\large ar^8=768$ $\large \frac{ar^8}{ar^2}=\frac{768}{12}$ $\large r^6=64$ $\large r=2 \ , \ r=-2$ I forgot the formulas and decided to go with this but i don't know if it is correct or even if it's acceptable... can anyone confirm for me please?
Mathematics
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• sasogeek
is it okay to do this...? and did i get it correct anyway? the third term of an exponential sequence is 12 and the 9th term is 768. find the values of the common ratio. $\large ar^2=12$$\large ar^8=768$ $\large \frac{ar^8}{ar^2}=\frac{768}{12}$ $\large r^6=64$ $\large r=2 \ , \ r=-2$ I forgot the formulas and decided to go with this but i don't know if it is correct or even if it's acceptable... can anyone confirm for me please?
Mathematics

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