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barrelracer23

  • 2 years ago

I need help with two questions, trying to study for finals... not for a grade! 1.)A park in a subdivision is triangular-shaped. Two adjacent sides of the park are 533 feet and 525 feet. The angle between the sides is 53°. Find the area of the park to the nearest square foot. 2.)The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. About how much room is there between the ball and the rim in a shot in which the ball goes in exactly in the center of the rim? Show your work.

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  1. barrelracer23
    • 2 years ago
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    i think the answer to the second question is 26. but im not sure

  2. TuringTest
    • 2 years ago
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    for 2) you need the radius of the ball and rim if the ball goes through the center of the hoop the space between the ball and the hoop will be the difference of their radii

  3. TuringTest
    • 2 years ago
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    from overhead the situation would look like this:|dw:1337013670261:dw|the radius can be found from the formula\[C=2\pi r\]where \(C\) is the circumference and \(r\) is the radius of any circle

  4. TuringTest
    • 2 years ago
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    I had intended that \(r_h\) represent the radius of the hoop and \(r_b\) the radius of the ball the space you want is then\[r_h-r_b\]|dw:1337013895916:dw|

  5. satellite73
    • 2 years ago
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    first one area is \[\frac{1}{2}bc\sin(A)\] for \[A=53, b=533, c=525\]

  6. barrelracer23
    • 2 years ago
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    so for the first one the area would be5486?

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