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Find one area of each triangle. Round intermediate values of the nearest tenth. Ust the rounded values to calcuate the next value. Round your final answer to the nearest tenth. Please help and show work! Drawing Below -->!

Mathematics
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|dw:1337035285613:dw|
So, what is the formula for area of a triangle?
a2 +b2= c2 and a= 1/2 bh.

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Other answers:

ok, so we have the height. We want to find the base length to plug into the area formula Of course, you went a step ahead and gave the next formula as well. We would have to use Pythagorean Theorem to determine the length of the base. a^2 + b^2 = c^2
So would it be a2 +8^2 =7^2
In a^2 + b^2 = c^2, the a^2 and b^2 represent the squared lengths of the legs of the triangle. The c^2 represents the hypotenuse length squared. |dw:1337037273817:dw|
So you'd have 7^2 + b^2 = 8^2. We'd solve for b there.
Ok so it would be 7^2 + b^2 = 8^2?
Yeah. :)
Once we find b there, we round it to the nearest tenth and then apply it in the area formula with the height 7 and that as the base.
So what would the total answer be for the a2 + b2 = c2?
7^2 + b^2 = 8^2 49 + b^2 = 64 b^2 = 15 b = sqrt{15} then you can evaluate this in calculator to round it to nearest tenth
I typed it in and squared rooted it and I still got 15
Hm maybe it was typed in wrong. I get sqrt(15) ~ 3.87298
So would the round to 4?
we round it to nearest tenth, so we look at the 3.87 and determine whether to keep 3.8 or go to 3.9
We would keep it at 3.9?
Yes, we use 3.9. So, just plug it into area formula \(A = \frac{1}{2} b h \) with b = 3.9 and h = 7 and solve for A. It looks like you have to round the value of A to nearest tenth also.
So, what I get is A = 1/2 (3.9) (7) = 13.65 = 13.7 rounded up to nearest tenth.

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