## 28Tylerr Group Title Find one area of each triangle. Round intermediate values of the nearest tenth. Ust the rounded values to calcuate the next value. Round your final answer to the nearest tenth. Please help and show work! Drawing Below -->! 2 years ago 2 years ago

1. 28Tylerr Group Title

|dw:1337035285613:dw|

2. AccessDenied Group Title

So, what is the formula for area of a triangle?

3. 28Tylerr Group Title

a2 +b2= c2 and a= 1/2 bh.

4. AccessDenied Group Title

ok, so we have the height. We want to find the base length to plug into the area formula Of course, you went a step ahead and gave the next formula as well. We would have to use Pythagorean Theorem to determine the length of the base. a^2 + b^2 = c^2

5. 28Tylerr Group Title

So would it be a2 +8^2 =7^2

6. AccessDenied Group Title

In a^2 + b^2 = c^2, the a^2 and b^2 represent the squared lengths of the legs of the triangle. The c^2 represents the hypotenuse length squared. |dw:1337037273817:dw|

7. AccessDenied Group Title

So you'd have 7^2 + b^2 = 8^2. We'd solve for b there.

8. 28Tylerr Group Title

Ok so it would be 7^2 + b^2 = 8^2?

9. AccessDenied Group Title

Yeah. :)

10. AccessDenied Group Title

Once we find b there, we round it to the nearest tenth and then apply it in the area formula with the height 7 and that as the base.

11. 28Tylerr Group Title

So what would the total answer be for the a2 + b2 = c2?

12. AccessDenied Group Title

7^2 + b^2 = 8^2 49 + b^2 = 64 b^2 = 15 b = sqrt{15} then you can evaluate this in calculator to round it to nearest tenth

13. 28Tylerr Group Title

I typed it in and squared rooted it and I still got 15

14. AccessDenied Group Title

Hm maybe it was typed in wrong. I get sqrt(15) ~ 3.87298

15. 28Tylerr Group Title

So would the round to 4?

16. AccessDenied Group Title

we round it to nearest tenth, so we look at the 3.87 and determine whether to keep 3.8 or go to 3.9

17. 28Tylerr Group Title

We would keep it at 3.9?

18. AccessDenied Group Title

Yes, we use 3.9. So, just plug it into area formula $$A = \frac{1}{2} b h$$ with b = 3.9 and h = 7 and solve for A. It looks like you have to round the value of A to nearest tenth also.

19. AccessDenied Group Title

So, what I get is A = 1/2 (3.9) (7) = 13.65 = 13.7 rounded up to nearest tenth.