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28Tylerr Group Title

Find one area of each triangle. Round intermediate values of the nearest tenth. Ust the rounded values to calcuate the next value. Round your final answer to the nearest tenth. Please help and show work! Drawing Below -->!

  • 2 years ago
  • 2 years ago

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  1. 28Tylerr Group Title
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    |dw:1337137612703:dw|

    • 2 years ago
  2. GOODMAN Group Title
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    Hmm...lol, the drawing is a bit unclear..

    • 2 years ago
  3. 28Tylerr Group Title
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    Lol, I know it's kind of hard to read.

    • 2 years ago
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    |dw:1337041518669:dw|

    • 2 years ago
  5. GOODMAN Group Title
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    I dont know where the 2 goes, lol.

    • 2 years ago
  6. 28Tylerr Group Title
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    There was no 2 and it was 5.2

    • 2 years ago
  7. GOODMAN Group Title
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    |dw:1337041626863:dw|

    • 2 years ago
  8. GOODMAN Group Title
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    Like that right?

    • 2 years ago
  9. 28Tylerr Group Title
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    Yepp

    • 2 years ago
  10. GOODMAN Group Title
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    |dw:1337041674389:dw|

    • 2 years ago
  11. GOODMAN Group Title
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    Thers a more clearer version.. As you can see, this looks like an isosceles.

    • 2 years ago
  12. 28Tylerr Group Title
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    Ahh, Yes it kinda looks like a triangle split in two

    • 2 years ago
  13. GOODMAN Group Title
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    Now..because of this one rule..lol, sorry forgot the rule, but remember its function, but it stated that that line in the middle, i think altitude its called, not sure, that separates the triangle, makes the two halves equal.

    • 2 years ago
  14. GOODMAN Group Title
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    So, basically, that means: |dw:1337041876443:dw|

    • 2 years ago
  15. 28Tylerr Group Title
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    Ok, Would I use the a2 + b2 = c2 and the a=1/2bh?

    • 2 years ago
  16. GOODMAN Group Title
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    Yes..I have found all the necessary lengths, all you need to do is plug it in to your formula.

    • 2 years ago
  17. GOODMAN Group Title
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    So.. What is our base?

    • 2 years ago
  18. 28Tylerr Group Title
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    Ok, Would it be like this: 7^2 + 7^2 = 5.2^2?

    • 2 years ago
  19. GOODMAN Group Title
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    No..wait.

    • 2 years ago
  20. 28Tylerr Group Title
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    Or would you add the 2 5.2's to make 10.4?

    • 2 years ago
  21. GOODMAN Group Title
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    |dw:1337042106132:dw|

    • 2 years ago
  22. GOODMAN Group Title
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    Use Pythagorean Theorem. Our hypotenuse, or "c" is 7 our leg 1 or "a" is 5.2 we need to find leg2 or "h"

    • 2 years ago
  23. 28Tylerr Group Title
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    Ok, So how would I set that up?

    • 2 years ago
  24. GOODMAN Group Title
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    \[a ^{2}+b ^{2}=c ^{2}\] \[(5.2)^{2}+b ^{2}=7^{2}\] \[27.04+b ^{2}=49\] \[27.04-Subtract \] \[b ^{2}=49-27.04\] \[b ^{2}=21.96\] \[b=4.7\]

    • 2 years ago
  25. GOODMAN Group Title
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    Our "b" will substitute as our "h" or height.

    • 2 years ago
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    |dw:1337042542370:dw|

    • 2 years ago
  27. GOODMAN Group Title
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    So, now we have all the components of our triangle. A=1/2bh A=1/2(10.4)(4.7) A=1/2(48.88) A=24.44

    • 2 years ago
  28. 28Tylerr Group Title
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    Would that be my answer and my answer for my area

    • 2 years ago
  29. GOODMAN Group Title
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    Yes..that would be your area.

    • 2 years ago
  30. 28Tylerr Group Title
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    Mhmmk, can you help me with 1 more like this?

    • 2 years ago
  31. GOODMAN Group Title
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    Okay..but I gotta hurry. I have some trig functions, lol.

    • 2 years ago
  32. 28Tylerr Group Title
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    |dw:1337140075755:dw|

    • 2 years ago
  33. GOODMAN Group Title
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    |dw:1337042863061:dw|

    • 2 years ago
  34. GOODMAN Group Title
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    Like that? Is it isosceles as well?

    • 2 years ago
  35. 28Tylerr Group Title
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    Yes

    • 2 years ago
  36. GOODMAN Group Title
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    Okay, because of the altitude, we can also determine this..|dw:1337042961699:dw|

    • 2 years ago
  37. 28Tylerr Group Title
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    Ok

    • 2 years ago
  38. GOODMAN Group Title
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    Now.. We have our formula. A=1/2bh Our Base: 16 And our height: 5

    • 2 years ago
  39. 28Tylerr Group Title
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    Can you show me some work for that plz on both? (:

    • 2 years ago
  40. GOODMAN Group Title
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    A=1/2bh A=1/2(16)(5) A=1/2(80) A=40

    • 2 years ago
  41. 28Tylerr Group Title
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    What about for a2 + b2 = c2

    • 2 years ago
  42. GOODMAN Group Title
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    We didn't need the Pythagorean Theorem, because we had all the necessary lengths to find the Area.

    • 2 years ago
  43. 28Tylerr Group Title
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    Oh ok so all I needed was the Area because

    • 2 years ago
  44. 28Tylerr Group Title
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    I had all of the lengths

    • 2 years ago
  45. GOODMAN Group Title
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    Yes..but the first one, we needed the height, and we used the Pythagorean Theorem to find it. In this problem, we already had everything we needed to find the Area.

    • 2 years ago
  46. 28Tylerr Group Title
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    Ok, I thank you for all of the help Goodman. Hopefully you can help me some more some other time. Thank You (:

    • 2 years ago
  47. GOODMAN Group Title
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    No Problem :D Iam glad I helped

    • 2 years ago
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