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28Tylerr
Group Title
Find one area of each triangle. Round intermediate values of the nearest tenth. Ust the rounded values to calcuate the next value. Round your final answer to the nearest tenth. Please help and show work! Drawing Below >!
 2 years ago
 2 years ago
28Tylerr Group Title
Find one area of each triangle. Round intermediate values of the nearest tenth. Ust the rounded values to calcuate the next value. Round your final answer to the nearest tenth. Please help and show work! Drawing Below >!
 2 years ago
 2 years ago

This Question is Closed

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
dw:1337137612703:dw
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Hmm...lol, the drawing is a bit unclear..
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
Lol, I know it's kind of hard to read.
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
dw:1337041518669:dw
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
I dont know where the 2 goes, lol.
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
There was no 2 and it was 5.2
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
dw:1337041626863:dw
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Like that right?
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
dw:1337041674389:dw
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Thers a more clearer version.. As you can see, this looks like an isosceles.
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
Ahh, Yes it kinda looks like a triangle split in two
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Now..because of this one rule..lol, sorry forgot the rule, but remember its function, but it stated that that line in the middle, i think altitude its called, not sure, that separates the triangle, makes the two halves equal.
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
So, basically, that means: dw:1337041876443:dw
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
Ok, Would I use the a2 + b2 = c2 and the a=1/2bh?
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Yes..I have found all the necessary lengths, all you need to do is plug it in to your formula.
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
So.. What is our base?
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
Ok, Would it be like this: 7^2 + 7^2 = 5.2^2?
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
Or would you add the 2 5.2's to make 10.4?
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
dw:1337042106132:dw
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Use Pythagorean Theorem. Our hypotenuse, or "c" is 7 our leg 1 or "a" is 5.2 we need to find leg2 or "h"
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
Ok, So how would I set that up?
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
\[a ^{2}+b ^{2}=c ^{2}\] \[(5.2)^{2}+b ^{2}=7^{2}\] \[27.04+b ^{2}=49\] \[27.04Subtract \] \[b ^{2}=4927.04\] \[b ^{2}=21.96\] \[b=4.7\]
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Our "b" will substitute as our "h" or height.
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
dw:1337042542370:dw
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
So, now we have all the components of our triangle. A=1/2bh A=1/2(10.4)(4.7) A=1/2(48.88) A=24.44
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
Would that be my answer and my answer for my area
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Yes..that would be your area.
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
Mhmmk, can you help me with 1 more like this?
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Okay..but I gotta hurry. I have some trig functions, lol.
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
dw:1337140075755:dw
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
dw:1337042863061:dw
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Like that? Is it isosceles as well?
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Okay, because of the altitude, we can also determine this..dw:1337042961699:dw
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Now.. We have our formula. A=1/2bh Our Base: 16 And our height: 5
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
Can you show me some work for that plz on both? (:
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
A=1/2bh A=1/2(16)(5) A=1/2(80) A=40
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
What about for a2 + b2 = c2
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
We didn't need the Pythagorean Theorem, because we had all the necessary lengths to find the Area.
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
Oh ok so all I needed was the Area because
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
I had all of the lengths
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Yes..but the first one, we needed the height, and we used the Pythagorean Theorem to find it. In this problem, we already had everything we needed to find the Area.
 2 years ago

28Tylerr Group TitleBest ResponseYou've already chosen the best response.0
Ok, I thank you for all of the help Goodman. Hopefully you can help me some more some other time. Thank You (:
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
No Problem :D Iam glad I helped
 2 years ago
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