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28Tylerr

  • 2 years ago

Find one area of each triangle. Round intermediate values of the nearest tenth. Ust the rounded values to calcuate the next value. Round your final answer to the nearest tenth. Please help and show work! Drawing Below -->!

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  1. 28Tylerr
    • 2 years ago
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    |dw:1337137612703:dw|

  2. GOODMAN
    • 2 years ago
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    Hmm...lol, the drawing is a bit unclear..

  3. 28Tylerr
    • 2 years ago
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    Lol, I know it's kind of hard to read.

  4. GOODMAN
    • 2 years ago
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    |dw:1337041518669:dw|

  5. GOODMAN
    • 2 years ago
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    I dont know where the 2 goes, lol.

  6. 28Tylerr
    • 2 years ago
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    There was no 2 and it was 5.2

  7. GOODMAN
    • 2 years ago
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    |dw:1337041626863:dw|

  8. GOODMAN
    • 2 years ago
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    Like that right?

  9. 28Tylerr
    • 2 years ago
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    Yepp

  10. GOODMAN
    • 2 years ago
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    |dw:1337041674389:dw|

  11. GOODMAN
    • 2 years ago
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    Thers a more clearer version.. As you can see, this looks like an isosceles.

  12. 28Tylerr
    • 2 years ago
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    Ahh, Yes it kinda looks like a triangle split in two

  13. GOODMAN
    • 2 years ago
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    Now..because of this one rule..lol, sorry forgot the rule, but remember its function, but it stated that that line in the middle, i think altitude its called, not sure, that separates the triangle, makes the two halves equal.

  14. GOODMAN
    • 2 years ago
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    So, basically, that means: |dw:1337041876443:dw|

  15. 28Tylerr
    • 2 years ago
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    Ok, Would I use the a2 + b2 = c2 and the a=1/2bh?

  16. GOODMAN
    • 2 years ago
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    Yes..I have found all the necessary lengths, all you need to do is plug it in to your formula.

  17. GOODMAN
    • 2 years ago
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    So.. What is our base?

  18. 28Tylerr
    • 2 years ago
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    Ok, Would it be like this: 7^2 + 7^2 = 5.2^2?

  19. GOODMAN
    • 2 years ago
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    No..wait.

  20. 28Tylerr
    • 2 years ago
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    Or would you add the 2 5.2's to make 10.4?

  21. GOODMAN
    • 2 years ago
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    |dw:1337042106132:dw|

  22. GOODMAN
    • 2 years ago
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    Use Pythagorean Theorem. Our hypotenuse, or "c" is 7 our leg 1 or "a" is 5.2 we need to find leg2 or "h"

  23. 28Tylerr
    • 2 years ago
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    Ok, So how would I set that up?

  24. GOODMAN
    • 2 years ago
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    \[a ^{2}+b ^{2}=c ^{2}\] \[(5.2)^{2}+b ^{2}=7^{2}\] \[27.04+b ^{2}=49\] \[27.04-Subtract \] \[b ^{2}=49-27.04\] \[b ^{2}=21.96\] \[b=4.7\]

  25. GOODMAN
    • 2 years ago
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    Our "b" will substitute as our "h" or height.

  26. GOODMAN
    • 2 years ago
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    |dw:1337042542370:dw|

  27. GOODMAN
    • 2 years ago
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    So, now we have all the components of our triangle. A=1/2bh A=1/2(10.4)(4.7) A=1/2(48.88) A=24.44

  28. 28Tylerr
    • 2 years ago
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    Would that be my answer and my answer for my area

  29. GOODMAN
    • 2 years ago
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    Yes..that would be your area.

  30. 28Tylerr
    • 2 years ago
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    Mhmmk, can you help me with 1 more like this?

  31. GOODMAN
    • 2 years ago
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    Okay..but I gotta hurry. I have some trig functions, lol.

  32. 28Tylerr
    • 2 years ago
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    |dw:1337140075755:dw|

  33. GOODMAN
    • 2 years ago
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    |dw:1337042863061:dw|

  34. GOODMAN
    • 2 years ago
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    Like that? Is it isosceles as well?

  35. 28Tylerr
    • 2 years ago
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    Yes

  36. GOODMAN
    • 2 years ago
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    Okay, because of the altitude, we can also determine this..|dw:1337042961699:dw|

  37. 28Tylerr
    • 2 years ago
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    Ok

  38. GOODMAN
    • 2 years ago
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    Now.. We have our formula. A=1/2bh Our Base: 16 And our height: 5

  39. 28Tylerr
    • 2 years ago
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    Can you show me some work for that plz on both? (:

  40. GOODMAN
    • 2 years ago
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    A=1/2bh A=1/2(16)(5) A=1/2(80) A=40

  41. 28Tylerr
    • 2 years ago
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    What about for a2 + b2 = c2

  42. GOODMAN
    • 2 years ago
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    We didn't need the Pythagorean Theorem, because we had all the necessary lengths to find the Area.

  43. 28Tylerr
    • 2 years ago
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    Oh ok so all I needed was the Area because

  44. 28Tylerr
    • 2 years ago
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    I had all of the lengths

  45. GOODMAN
    • 2 years ago
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    Yes..but the first one, we needed the height, and we used the Pythagorean Theorem to find it. In this problem, we already had everything we needed to find the Area.

  46. 28Tylerr
    • 2 years ago
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    Ok, I thank you for all of the help Goodman. Hopefully you can help me some more some other time. Thank You (:

  47. GOODMAN
    • 2 years ago
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    No Problem :D Iam glad I helped

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