anonymous
  • anonymous
Find one area of each triangle. Round intermediate values of the nearest tenth. Ust the rounded values to calcuate the next value. Round your final answer to the nearest tenth. Please help and show work! Drawing Below -->!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1337137612703:dw|
anonymous
  • anonymous
Hmm...lol, the drawing is a bit unclear..
anonymous
  • anonymous
Lol, I know it's kind of hard to read.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
|dw:1337041518669:dw|
anonymous
  • anonymous
I dont know where the 2 goes, lol.
anonymous
  • anonymous
There was no 2 and it was 5.2
anonymous
  • anonymous
|dw:1337041626863:dw|
anonymous
  • anonymous
Like that right?
anonymous
  • anonymous
Yepp
anonymous
  • anonymous
|dw:1337041674389:dw|
anonymous
  • anonymous
Thers a more clearer version.. As you can see, this looks like an isosceles.
anonymous
  • anonymous
Ahh, Yes it kinda looks like a triangle split in two
anonymous
  • anonymous
Now..because of this one rule..lol, sorry forgot the rule, but remember its function, but it stated that that line in the middle, i think altitude its called, not sure, that separates the triangle, makes the two halves equal.
anonymous
  • anonymous
So, basically, that means: |dw:1337041876443:dw|
anonymous
  • anonymous
Ok, Would I use the a2 + b2 = c2 and the a=1/2bh?
anonymous
  • anonymous
Yes..I have found all the necessary lengths, all you need to do is plug it in to your formula.
anonymous
  • anonymous
So.. What is our base?
anonymous
  • anonymous
Ok, Would it be like this: 7^2 + 7^2 = 5.2^2?
anonymous
  • anonymous
No..wait.
anonymous
  • anonymous
Or would you add the 2 5.2's to make 10.4?
anonymous
  • anonymous
|dw:1337042106132:dw|
anonymous
  • anonymous
Use Pythagorean Theorem. Our hypotenuse, or "c" is 7 our leg 1 or "a" is 5.2 we need to find leg2 or "h"
anonymous
  • anonymous
Ok, So how would I set that up?
anonymous
  • anonymous
\[a ^{2}+b ^{2}=c ^{2}\] \[(5.2)^{2}+b ^{2}=7^{2}\] \[27.04+b ^{2}=49\] \[27.04-Subtract \] \[b ^{2}=49-27.04\] \[b ^{2}=21.96\] \[b=4.7\]
anonymous
  • anonymous
Our "b" will substitute as our "h" or height.
anonymous
  • anonymous
|dw:1337042542370:dw|
anonymous
  • anonymous
So, now we have all the components of our triangle. A=1/2bh A=1/2(10.4)(4.7) A=1/2(48.88) A=24.44
anonymous
  • anonymous
Would that be my answer and my answer for my area
anonymous
  • anonymous
Yes..that would be your area.
anonymous
  • anonymous
Mhmmk, can you help me with 1 more like this?
anonymous
  • anonymous
Okay..but I gotta hurry. I have some trig functions, lol.
anonymous
  • anonymous
|dw:1337140075755:dw|
anonymous
  • anonymous
|dw:1337042863061:dw|
anonymous
  • anonymous
Like that? Is it isosceles as well?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
Okay, because of the altitude, we can also determine this..|dw:1337042961699:dw|
anonymous
  • anonymous
Ok
anonymous
  • anonymous
Now.. We have our formula. A=1/2bh Our Base: 16 And our height: 5
anonymous
  • anonymous
Can you show me some work for that plz on both? (:
anonymous
  • anonymous
A=1/2bh A=1/2(16)(5) A=1/2(80) A=40
anonymous
  • anonymous
What about for a2 + b2 = c2
anonymous
  • anonymous
We didn't need the Pythagorean Theorem, because we had all the necessary lengths to find the Area.
anonymous
  • anonymous
Oh ok so all I needed was the Area because
anonymous
  • anonymous
I had all of the lengths
anonymous
  • anonymous
Yes..but the first one, we needed the height, and we used the Pythagorean Theorem to find it. In this problem, we already had everything we needed to find the Area.
anonymous
  • anonymous
Ok, I thank you for all of the help Goodman. Hopefully you can help me some more some other time. Thank You (:
anonymous
  • anonymous
No Problem :D Iam glad I helped

Looking for something else?

Not the answer you are looking for? Search for more explanations.