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|dw:1337137612703:dw|

Hmm...lol, the drawing is a bit unclear..

Lol, I know it's kind of hard to read.

|dw:1337041518669:dw|

I dont know where the 2 goes, lol.

There was no 2 and it was 5.2

|dw:1337041626863:dw|

Like that right?

Yepp

|dw:1337041674389:dw|

Thers a more clearer version..
As you can see, this looks like an isosceles.

Ahh, Yes it kinda looks like a triangle split in two

So, basically, that means:
|dw:1337041876443:dw|

Ok, Would I use the a2 + b2 = c2 and the a=1/2bh?

Yes..I have found all the necessary lengths, all you need to do is plug it in to your formula.

So..
What is our base?

Ok, Would it be like this: 7^2 + 7^2 = 5.2^2?

No..wait.

Or would you add the 2 5.2's to make 10.4?

|dw:1337042106132:dw|

Ok, So how would I set that up?

Our "b" will substitute as our "h" or height.

|dw:1337042542370:dw|

So, now we have all the components of our triangle.
A=1/2bh
A=1/2(10.4)(4.7)
A=1/2(48.88)
A=24.44

Would that be my answer and my answer for my area

Yes..that would be your area.

Mhmmk, can you help me with 1 more like this?

Okay..but I gotta hurry. I have some trig functions, lol.

|dw:1337140075755:dw|

|dw:1337042863061:dw|

Like that? Is it isosceles as well?

Yes

Okay, because of the altitude, we can also determine this..|dw:1337042961699:dw|

Ok

Now..
We have our formula.
A=1/2bh
Our Base: 16
And our height: 5

Can you show me some work for that plz on both? (:

A=1/2bh
A=1/2(16)(5)
A=1/2(80)
A=40

What about for a2 + b2 = c2

We didn't need the Pythagorean Theorem, because we had all the necessary lengths to find the Area.

Oh ok so all I needed was the Area because

I had all of the lengths

No Problem :D Iam glad I helped