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j.giudice13
Group Title
What is the solution to the equation 2^(1 + 2x )= 3 ?
 2 years ago
 2 years ago
j.giudice13 Group Title
What is the solution to the equation 2^(1 + 2x )= 3 ?
 2 years ago
 2 years ago

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dpaInc Group TitleBest ResponseYou've already chosen the best response.1
2^(1 + 2x )= 3 take the log_2 of both sides: 1+2x = log_2 3 subtract 1 from both sides: 2x = (log_2 3)  1 divide by 2 x = [(log_2 3)  1]/2
 2 years ago

j.giudice13 Group TitleBest ResponseYou've already chosen the best response.1
1/2 isnt an option....
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
you didn't specify the way you wanted the solution... and 1/2 is not what I came up with. it's x = [(log_2 3)  1]/2 did you want a calculator answer?
 2 years ago

j.giudice13 Group TitleBest ResponseYou've already chosen the best response.1
umm, yea let me see what that looks like
 2 years ago

j.giudice13 Group TitleBest ResponseYou've already chosen the best response.1
i dont have a calculator :(
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
computer calculator?
 2 years ago

j.giudice13 Group TitleBest ResponseYou've already chosen the best response.1
i have so many windows up lol
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
just one more won't hurt http://www.wolframalpha.com
 2 years ago

j.giudice13 Group TitleBest ResponseYou've already chosen the best response.1
i just need an answer to see if i did this right
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
what did you get? I gave you a calculator...
 2 years ago

j.giudice13 Group TitleBest ResponseYou've already chosen the best response.1
my computer will crash. its old i got .185
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=%5B%28log_2+3%29++1%5D%2F2 if that doesn't work use a calculator from the applications section. Those have been there since time immemorial.
 2 years ago

j.giudice13 Group TitleBest ResponseYou've already chosen the best response.1
is that the right answer
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
0.292... is the "right" answer. If you want the most accurate answer you take the thing with the log.
 2 years ago

j.giudice13 Group TitleBest ResponseYou've already chosen the best response.1
thank you very much. simple is all i need
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.1
:) you are welcome
 2 years ago
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