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2^(1 + 2x )= 3 take the log_2 of both sides: 1+2x = log_2 3 subtract 1 from both sides: 2x = (log_2 3) - 1 divide by 2 x = [(log_2 3) - 1]/2
-1/2 isnt an option....
you didn't specify the way you wanted the solution... and -1/2 is not what I came up with. it's x = [(log_2 3) - 1]/2 did you want a calculator answer?
umm, yea let me see what that looks like
i dont have a calculator :(
i have so many windows up lol
just one more won't hurt http://www.wolframalpha.com
i just need an answer to see if i did this right
what did you get? I gave you a calculator...
my computer will crash. its old i got .185
http://www.wolframalpha.com/input/?i=%5B%28log_2+3%29+-+1%5D%2F2 if that doesn't work use a calculator from the applications section. Those have been there since time immemorial.
is that the right answer
0.292... is the "right" answer. If you want the most accurate answer you take the thing with the log.
thank you very much. simple is all i need
:) you are welcome