anonymous
  • anonymous
A.s Problem : ____________ Find A.s if the sum of all terms starting from the second term is (-36) and the sum of all terms except the last term is Zero and the difference between the sixth term and the tenth term is equal to 16. _________________________
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
inkyvoyd
  • inkyvoyd
No LaTex, not interested.
anonymous
  • anonymous
@experimentX :If u have time :)
experimentX
  • experimentX
let, \( n\) be the number of terms!! given, \( S_n - a = -36 \implies \frac{n (a+l)}{2} - a = -36\) or \( \frac{n (2a+(n-1)d)}{n} - a = -36\) -------- 1 \( S_n - l = 0 \implies \frac{n (a+l)}{2} - l = 0\) or, \frac{n(2a+(n-1)d)}{n} - a - (n-1)d = 0\) -------- 2 <-- also it implies that AP must be And \( a + (5-1)d - (a + (10-1)d = 16 \) ---- 3 3 unknown variables and three equations ... it should be solveable!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

experimentX
  • experimentX
Ah ... that n in 1 down there is supposed to be 2
anonymous
  • anonymous
aha ,I got it :) ,TYSM for your time :) @experimentX
experimentX
  • experimentX
yw ..

Looking for something else?

Not the answer you are looking for? Search for more explanations.