## anonymous 4 years ago A.s Problem : ____________ Find A.s if the sum of all terms starting from the second term is (-36) and the sum of all terms except the last term is Zero and the difference between the sixth term and the tenth term is equal to 16. _________________________

1. inkyvoyd

No LaTex, not interested.

2. anonymous

@experimentX :If u have time :)

3. experimentX

let, $$n$$ be the number of terms!! given, $$S_n - a = -36 \implies \frac{n (a+l)}{2} - a = -36$$ or $$\frac{n (2a+(n-1)d)}{n} - a = -36$$ -------- 1 $$S_n - l = 0 \implies \frac{n (a+l)}{2} - l = 0$$ or, \frac{n(2a+(n-1)d)}{n} - a - (n-1)d = 0\) -------- 2 <-- also it implies that AP must be And $$a + (5-1)d - (a + (10-1)d = 16$$ ---- 3 3 unknown variables and three equations ... it should be solveable!!

4. experimentX

Ah ... that n in 1 down there is supposed to be 2

5. anonymous

aha ,I got it :) ,TYSM for your time :) @experimentX

6. experimentX

yw ..