At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the **expert** answer you'll need to create a **free** account at **Brainly**

r^2=(x-2)^2+(y-(-4))^2
hold on i'll find r

why is it not\[r^2=(x+4)^2+(y-2)^2\]?

oh no wait I remember...

the formula for a circle with center (h,k) is
r^2=(y-k)^2+(x-h)^2

more info
http://www.regentsprep.org/Regents/math/algtrig/ATC1/circlelesson.htm

there is no more info

yeah, but those links always confuse me
and then how do you find r again, isn't there some easy way?

well they tell you the center of the circle, so we know h and k

yes colorful you have it a little mixed around (x-h)^2+(y-k)^2=r^2

yes now i just have to write the equation

i think we use d formula

radius would be 5 i think

we still gotta find r though
is it 5 ?
let me check...

so final answer (x-2)^2+(y+4)=5

think thaty is right does that 4 become positive on the y

|dw:1337146127268:dw|I don't think the radius is 5
why do you think it's 5 ???

d=square root of 4-2 +-1-(-4) square root of 2+3 Square root of 5

\[d=\sqrt{(4-2)^2+(-1-(-4))^2}=\sqrt{2^2+3^2}\]

im coming up with (x-2)^2+(y+4)^2=5 will someone verify or tell me where im wrong

good thinking colorful i did that before

but it doesn't give 5...

radius is 13

sqrt(13)

which in my notes we had sqrt 18 we put radius as 18

um... don't know what to tell you about that, sorry :(

maybe there's a typo, or you copied something wrong?

so answer would be (x-2)^2+(y+4)^2=13

yeah, looks like it

thank you colorful for helping and pointing out mistake

no problem :D
welcome!

A Mathematica version of the solution with comments and a plot is attached.