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Amy876

  • 2 years ago

10/52 reduced

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  1. ParthKohli
    • 2 years ago
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    Divide both numerator and denominator by 2.

  2. fewscrewsmissing
    • 2 years ago
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    Try dividing the numerator and denominator by their highest common multiple. Maybe 2?

  3. Andresfon12
    • 2 years ago
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    agree with parth

  4. ParthKohli
    • 2 years ago
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    \(\Large \color{MidnightBlue}{\rightarrow {10 \div 2 \over 52 \div 2} }\) \(\Large \color{MidnightBlue}{\rightarrow {5 \over 26} }\)

  5. Amy876
    • 2 years ago
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    5/26?

  6. Andresfon12
    • 2 years ago
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    |dw:1337186461340:dw|

  7. ParthKohli
    • 2 years ago
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    Yep!

  8. Amy876
    • 2 years ago
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    ok thanks :D

  9. fewscrewsmissing
    • 2 years ago
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    *Factor, sorry. And yes that's right.

  10. Andresfon12
    • 2 years ago
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    that correct

  11. Andresfon12
    • 2 years ago
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    if u mutiply the 2 back is the same

  12. ParthKohli
    • 2 years ago
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    Another way to say is: \(\Large \color{MidnightBlue}{\rightarrow {10 \over 52} = {5 \over 26} }\)

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