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Amy876 Group Title

10/52 reduced

  • 2 years ago
  • 2 years ago

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  1. ParthKohli Group Title
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    Divide both numerator and denominator by 2.

    • 2 years ago
  2. fewscrewsmissing Group Title
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    Try dividing the numerator and denominator by their highest common multiple. Maybe 2?

    • 2 years ago
  3. Andresfon12 Group Title
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    agree with parth

    • 2 years ago
  4. ParthKohli Group Title
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    \(\Large \color{MidnightBlue}{\rightarrow {10 \div 2 \over 52 \div 2} }\) \(\Large \color{MidnightBlue}{\rightarrow {5 \over 26} }\)

    • 2 years ago
  5. Amy876 Group Title
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    5/26?

    • 2 years ago
  6. Andresfon12 Group Title
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    |dw:1337186461340:dw|

    • 2 years ago
  7. ParthKohli Group Title
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    Yep!

    • 2 years ago
  8. Amy876 Group Title
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    ok thanks :D

    • 2 years ago
  9. fewscrewsmissing Group Title
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    *Factor, sorry. And yes that's right.

    • 2 years ago
  10. Andresfon12 Group Title
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    that correct

    • 2 years ago
  11. Andresfon12 Group Title
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    if u mutiply the 2 back is the same

    • 2 years ago
  12. ParthKohli Group Title
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    Another way to say is: \(\Large \color{MidnightBlue}{\rightarrow {10 \over 52} = {5 \over 26} }\)

    • 2 years ago
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