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 2 years ago
Hey guys! I would just like to ask if my partial differentiating is correct.
f(x,y)=xy (sin (4yx^2))
fyx = sin 4yx^2 + (8yx^2)(cos 4yx^2) + (12yx^2)(cos 4yx^2)  32(x^4)(y^2)(sin 4yx^2)
Thanks!
 2 years ago
Hey guys! I would just like to ask if my partial differentiating is correct. f(x,y)=xy (sin (4yx^2)) fyx = sin 4yx^2 + (8yx^2)(cos 4yx^2) + (12yx^2)(cos 4yx^2)  32(x^4)(y^2)(sin 4yx^2) Thanks!

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ash2326
 2 years ago
Best ResponseYou've already chosen the best response.0You have differentiated with respect to x or y?

imagreencat
 2 years ago
Best ResponseYou've already chosen the best response.0Well, fyx. So I first diff with respect to y then with respect to x. :)

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2it's the mixed derivative? let me check...

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2\[f_x=y\sin(4yx^2)+8x^2y^2\sin(4x^2y)\cos(4x^2y)\]I'm typing it out so we can all see if I make a mistake...

imagreencat
 2 years ago
Best ResponseYou've already chosen the best response.0Fy first. :) Then diff Fy with respect to x.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2the order shouldn't matter I don't think\[f_{xy}=\sin(4yx^2)+4yx^2\cos(4yx^2)+\frac{\partial}{\partial y}[8x^2y^2\sin(4x^2y)\cos(4x^2y)]\]

imagreencat
 2 years ago
Best ResponseYou've already chosen the best response.0Actually in some cases the order does not matter. But in others, it does. Anyway, thank you turing test! :)

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2oh but I have a 16...

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2I'll do it the other way on paper to see if that makes a diff

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2ok I redid it the other way and got the same answer as you sorry for the confusion

imagreencat
 2 years ago
Best ResponseYou've already chosen the best response.0It's okay Turing Test. I'm sorry for taking some of your time. :))) But, thanks again. I appreciate your effort.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2no it's my fault for messing up the first time you're welcome
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