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Sandiego19
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1337230739451:dw

Sandiego19
 2 years ago
Best ResponseYou've already chosen the best response.0the numbers are 29, 20, 21

sritama
 2 years ago
Best ResponseYou've already chosen the best response.0is it a right angled triangle ??/

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.0all you have to do is use similarity. see what angles are the same.

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.0and then use proportions. As you can see, the sides 29 and b are proportional, because the hypotenuse of the two similar triangles. same goes ofr the other sides. like this: actually it's 29/b=20/21=21/a for b: 29/b=20/21 b=(20/21)29 for a: 21/a=20/21 a=(20/21)21 get it?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2you have the right idea nickymarden, but you have the wrong values It should be a/20 = 20/21 which after solving for 'a' gives you a = 400/21 and b/20 = 29/21 which gives you b = 580/21

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.0haha, yeah you're right. sorry. it's 2 am here, can't blame me..

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2But I love this way better. I was set to use the pythagorean theorem until you wrote that lol

SmoothMath
 2 years ago
Best ResponseYou've already chosen the best response.0I don't think there is any way to. Is there, Jim?

Sandiego19
 2 years ago
Best ResponseYou've already chosen the best response.0SO , A = 400/21 And B = 580/21

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.0yes love, i'm sorry. @jim_thompson5910 is right :)

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2what do you mean SmoothMath?

SmoothMath
 2 years ago
Best ResponseYou've already chosen the best response.0I don't think that good ol' Pythag can solve this problem.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2Since we have two right triangles, we can say b^2 + 29^2 = (21+a)^2 and a^2+20^2 = b^2 So we have a system of two equations with 2 unknowns. This means we can solve for a and b.

SmoothMath
 2 years ago
Best ResponseYou've already chosen the best response.0Except that you're assuming this is a right angle, and that is not given: dw:1337232422096:dw

SmoothMath
 2 years ago
Best ResponseYou've already chosen the best response.0Ah, but it can be proven.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2it's not explicit, but the fact that the two triangles are similar allows us to use either method

SmoothMath
 2 years ago
Best ResponseYou've already chosen the best response.0But a roundabout way to solve it indeed. Haha, funny that it's the first way you thought of.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.2lol just been using it a lot more than the other method I guess
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