Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Sandiego19

  • 3 years ago

Can Someone Please Explain Me In Steps How To Solve For a and b ?

  • This Question is Closed
  1. Sandiego19
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1337230739451:dw|

  2. Sandiego19
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the numbers are 29, 20, 21

  3. sritama
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is it a right angled triangle ??/

  4. nickymarden
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    all you have to do is use similarity. see what angles are the same.

  5. nickymarden
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and then use proportions. As you can see, the sides 29 and b are proportional, because the hypotenuse of the two similar triangles. same goes ofr the other sides. like this: actually it's 29/b=20/21=21/a for b: 29/b=20/21 b=(20/21)29 for a: 21/a=20/21 a=(20/21)21 get it?

  6. Sandiego19
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes Thanks Alot :)

  7. jim_thompson5910
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you have the right idea nickymarden, but you have the wrong values It should be a/20 = 20/21 which after solving for 'a' gives you a = 400/21 and b/20 = 29/21 which gives you b = 580/21

  8. nickymarden
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    haha, yeah you're right. sorry. it's 2 am here, can't blame me..

  9. jim_thompson5910
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    But I love this way better. I was set to use the pythagorean theorem until you wrote that lol

  10. SmoothMath
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't think there is any way to. Is there, Jim?

  11. Sandiego19
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    SO , A = 400/21 And B = 580/21

  12. nickymarden
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes love, i'm sorry. @jim_thompson5910 is right :)

  13. Sandiego19
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its okay thanks

  14. jim_thompson5910
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    what do you mean SmoothMath?

  15. SmoothMath
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't think that good ol' Pythag can solve this problem.

  16. jim_thompson5910
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Since we have two right triangles, we can say b^2 + 29^2 = (21+a)^2 and a^2+20^2 = b^2 So we have a system of two equations with 2 unknowns. This means we can solve for a and b.

  17. SmoothMath
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Except that you're assuming this is a right angle, and that is not given: |dw:1337232422096:dw|

  18. SmoothMath
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ah, but it can be proven.

  19. jim_thompson5910
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    exactly

  20. SmoothMath
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Very good.

  21. jim_thompson5910
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    it's not explicit, but the fact that the two triangles are similar allows us to use either method

  22. SmoothMath
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    But a roundabout way to solve it indeed. Haha, funny that it's the first way you thought of.

  23. jim_thompson5910
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    lol just been using it a lot more than the other method I guess

  24. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy