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Shonengetsu

  • 3 years ago

Calculate the freezing point of a 2.6-molal aqueous sucrose solution. The freezing point depression constant for water is 1.86 degrees C/molal. 4.8 °C 1.4 °C -1.4 °C -4.8 °C

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  1. shivam_bhalla
    • 3 years ago
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    \[\delta T_f = K_f * m\] Where delta T_f is change in freezing point K_f-->freezing constant m-->molality

  2. Shonengetsu
    • 3 years ago
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    \[Tf = 1.86 * 2.6\]So it would be?

  3. Kryten
    • 3 years ago
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    yes

  4. Kryten
    • 3 years ago
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    - 4,8 °C !!!

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