int. dx/ (x^2 +2x+10) using partial fraction. please.

- anonymous

int. dx/ (x^2 +2x+10) using partial fraction. please.

- schrodinger

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- .Sam.

you can't factor that

- .Sam.

best approach is to complete the square and then trig substitution

- wasiqss

yehh, it will have complex factors

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

yup

- anonymous

@lilMissMindset To complete the square
x^2 +2x+10= x^2+2x+1+9 = (x+1)^2 +3^2
\[\int\limits_{}^{}\frac{dx}{(x+1)^2+3^2}\]
Now complete the rest

- anonymous

Remember
\[\int\limits_{}^{}\frac{dt}{x^2+a^2} = \frac{1}{a} \tan^{-1}(\frac{x}{a})\]

- anonymous

You can eaily prove the above by substituting x = atan(theta)

- anonymous

@shivam_bhalla she said partial fraction

- TuringTest

but it cannot be done with partial fraction if it cannot be factored

- wasiqss

traile , it willl become very complex then

- anonymous

yeah, im supposed to use that, partial fraction

- anonymous

@LOL, whjy do you want to complicate things when there is a aeasier method available. If you still insist on partial fraction, then it is fine

- wasiqss

lil miss it will only have complex factors

- TuringTest

there is either a typo, or it's impossible

- anonymous

*why

- TuringTest

I mean that using partial fractions is impossible... or at least redundant

- anonymous

what am i going to do about this problem then?

- anonymous

Take x+1 = t
dx=dt
You still get the same thing with partial fractions too

- TuringTest

how would you do this with partial fractions?
I don't see it... perhaps I am wrong though, it wouldn't be the first time :P

- anonymous

do you think quadratic factors can be use

- anonymous

\[\frac{1}{t^2+9} = \frac{At+B}{t^2+9}\]
we see a = 0, B=1
We again get back the same thing. So partail fraction approach should be useless

- anonymous

*partial

- TuringTest

like I said then, it's just redundant

- TuringTest

by impossible, I meant that the operation is useless, as you just said

- wasiqss

you fail turing xD lol jk

- TuringTest

@lilMissMindset are you \(sure\) there isn't a typo in your post?

- anonymous

yea. im quite sure i typed it right.

- anonymous

let's ignore the partial fraction thingy then.

- TuringTest

then shivam bhalla has shown you the right way
do you know trig substitution integrals?

- anonymous

yeah. i'm sorry, i'll do it using trig substitution. thank you so much.

- TuringTest

welcome!

Looking for something else?

Not the answer you are looking for? Search for more explanations.