Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

lilMissMindset

  • 3 years ago

int. dx/ (x^2 +2x+10) using partial fraction. please.

  • This Question is Closed
  1. .Sam.
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you can't factor that

  2. .Sam.
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    best approach is to complete the square and then trig substitution

  3. wasiqss
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yehh, it will have complex factors

  4. traile
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yup

  5. shivam_bhalla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @lilMissMindset To complete the square x^2 +2x+10= x^2+2x+1+9 = (x+1)^2 +3^2 \[\int\limits_{}^{}\frac{dx}{(x+1)^2+3^2}\] Now complete the rest

  6. shivam_bhalla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Remember \[\int\limits_{}^{}\frac{dt}{x^2+a^2} = \frac{1}{a} \tan^{-1}(\frac{x}{a})\]

  7. shivam_bhalla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    You can eaily prove the above by substituting x = atan(theta)

  8. traile
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @shivam_bhalla she said partial fraction

  9. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    but it cannot be done with partial fraction if it cannot be factored

  10. wasiqss
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    traile , it willl become very complex then

  11. lilMissMindset
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah, im supposed to use that, partial fraction

  12. shivam_bhalla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @LOL, whjy do you want to complicate things when there is a aeasier method available. If you still insist on partial fraction, then it is fine

  13. wasiqss
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lil miss it will only have complex factors

  14. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    there is either a typo, or it's impossible

  15. shivam_bhalla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    *why

  16. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I mean that using partial fractions is impossible... or at least redundant

  17. lilMissMindset
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what am i going to do about this problem then?

  18. shivam_bhalla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Take x+1 = t dx=dt You still get the same thing with partial fractions too

  19. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    how would you do this with partial fractions? I don't see it... perhaps I am wrong though, it wouldn't be the first time :P

  20. traile
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    do you think quadratic factors can be use

  21. shivam_bhalla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[\frac{1}{t^2+9} = \frac{At+B}{t^2+9}\] we see a = 0, B=1 We again get back the same thing. So partail fraction approach should be useless

  22. shivam_bhalla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    *partial

  23. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    like I said then, it's just redundant

  24. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    by impossible, I meant that the operation is useless, as you just said

  25. wasiqss
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you fail turing xD lol jk

  26. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @lilMissMindset are you \(sure\) there isn't a typo in your post?

  27. lilMissMindset
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yea. im quite sure i typed it right.

  28. lilMissMindset
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    let's ignore the partial fraction thingy then.

  29. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    then shivam bhalla has shown you the right way do you know trig substitution integrals?

  30. lilMissMindset
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah. i'm sorry, i'll do it using trig substitution. thank you so much.

  31. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    welcome!

  32. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy