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A firecracker has dimensions as shown. Height is 14 cm, radius is 1 cm and slant height of the cone is 2 cm. Paper covers the entire surface area including the cone, the lateral area and the bottom circle but does not include the tail. What is the best approximate area of paper needed to wrap the firecracker? (Use for . Round your answer to the nearest whole number.)

Mathematics
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you have 2 different shapes. a cilinder and a cone. to calculate the whole area you will need to calculate the total area of the cilinder and the total area of the cone. \[Acone= pi * r^2\] \[Acilinder=2*π*r*h + 2π*r2 \]
\[pi=3.14\]

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Other answers:

yes.
can you set the problum up with me?
yes, sure.
OK
\[Acone: 3,14*1^2\]
= 3.14
\[Acilinder=2*3,14*1*14+2*3,14*1^2\]
then: Acone+Acilinder
and that is your answer :)
hold up please
=287.4888
:)
thats not the answrs i have. thought
\[100cm2 power 97cm to 2 power 91cm2 power 104cm2
well, those are the formulas :x
didd i do the math wrong? can yuu coculated them 2
the answer is 97.2
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see
yees, i just told you the answer lol
no...! lol jk
haha

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