anonymous
  • anonymous
A firecracker has dimensions as shown. Height is 14 cm, radius is 1 cm and slant height of the cone is 2 cm. Paper covers the entire surface area including the cone, the lateral area and the bottom circle but does not include the tail. What is the best approximate area of paper needed to wrap the firecracker? (Use for . Round your answer to the nearest whole number.)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
you have 2 different shapes. a cilinder and a cone. to calculate the whole area you will need to calculate the total area of the cilinder and the total area of the cone. \[Acone= pi * r^2\] \[Acilinder=2*π*r*h + 2π*r2 \]
anonymous
  • anonymous
\[pi=3.14\]

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anonymous
  • anonymous
yes.
anonymous
  • anonymous
can you set the problum up with me?
anonymous
  • anonymous
yes, sure.
anonymous
  • anonymous
OK
anonymous
  • anonymous
\[Acone: 3,14*1^2\]
anonymous
  • anonymous
= 3.14
anonymous
  • anonymous
\[Acilinder=2*3,14*1*14+2*3,14*1^2\]
anonymous
  • anonymous
then: Acone+Acilinder
anonymous
  • anonymous
and that is your answer :)
anonymous
  • anonymous
hold up please
anonymous
  • anonymous
=287.4888
anonymous
  • anonymous
:)
anonymous
  • anonymous
thats not the answrs i have. thought
anonymous
  • anonymous
\[100cm2 power 97cm to 2 power 91cm2 power 104cm2
anonymous
  • anonymous
well, those are the formulas :x
anonymous
  • anonymous
didd i do the math wrong? can yuu coculated them 2
anonymous
  • anonymous
the answer is 97.2
anonymous
  • anonymous
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anonymous
  • anonymous
see
anonymous
  • anonymous
yees, i just told you the answer lol
anonymous
  • anonymous
no...! lol jk
anonymous
  • anonymous
haha

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