Apellot7
A firecracker has dimensions as shown. Height is 14 cm, radius is 1 cm and slant height of the cone is 2 cm.
Paper covers the entire surface area including the cone, the lateral area and the bottom circle but does not include the tail.
What is the best approximate area of paper needed to wrap the firecracker?
(Use for . Round your answer to the nearest whole number.)
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Apellot7
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nickymarden
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you have 2 different shapes. a cilinder and a cone. to calculate the whole area you will need to calculate the total area of the cilinder and the total area of the cone.
\[Acone= pi * r^2\]
\[Acilinder=2*π*r*h + 2π*r2 \]
Apellot7
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\[pi=3.14\]
nickymarden
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yes.
Apellot7
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can you set the problum up with me?
nickymarden
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yes, sure.
Apellot7
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OK
nickymarden
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\[Acone: 3,14*1^2\]
Apellot7
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= 3.14
nickymarden
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\[Acilinder=2*3,14*1*14+2*3,14*1^2\]
nickymarden
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then:
Acone+Acilinder
nickymarden
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and that is your answer :)
Apellot7
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hold up please
Apellot7
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=287.4888
nickymarden
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:)
Apellot7
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thats not the answrs i have. thought
Apellot7
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\[100cm2 power
97cm to 2 power
91cm2 power
104cm2
nickymarden
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well, those are the formulas :x
Apellot7
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didd i do the math wrong? can yuu coculated them 2
nickymarden
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the answer is 97.2
Apellot7
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Apellot7
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see
nickymarden
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yees, i just told you the answer lol
Apellot7
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no...! lol jk
nickymarden
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haha