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- anonymous

A firecracker has dimensions as shown. Height is 14 cm, radius is 1 cm and slant height of the cone is 2 cm.
Paper covers the entire surface area including the cone, the lateral area and the bottom circle but does not include the tail.
What is the best approximate area of paper needed to wrap the firecracker?
(Use for . Round your answer to the nearest whole number.)

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- anonymous

- schrodinger

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- anonymous

- anonymous

you have 2 different shapes. a cilinder and a cone. to calculate the whole area you will need to calculate the total area of the cilinder and the total area of the cone.
\[Acone= pi * r^2\]
\[Acilinder=2*π*r*h + 2π*r2 \]

- anonymous

\[pi=3.14\]

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- anonymous

yes.

- anonymous

can you set the problum up with me?

- anonymous

yes, sure.

- anonymous

OK

- anonymous

\[Acone: 3,14*1^2\]

- anonymous

= 3.14

- anonymous

\[Acilinder=2*3,14*1*14+2*3,14*1^2\]

- anonymous

then:
Acone+Acilinder

- anonymous

and that is your answer :)

- anonymous

hold up please

- anonymous

=287.4888

- anonymous

:)

- anonymous

thats not the answrs i have. thought

- anonymous

\[100cm2 power
97cm to 2 power
91cm2 power
104cm2

- anonymous

well, those are the formulas :x

- anonymous

didd i do the math wrong? can yuu coculated them 2

- anonymous

the answer is 97.2

- anonymous

- anonymous

see

- anonymous

yees, i just told you the answer lol

- anonymous

no...! lol jk

- anonymous

haha

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