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ajprincess
Plzz help A wire of 1m long carries a current of 10A and makes an angle of 30degrees with the uniform magnetic field B=1.5T. Calculate the magnitude and the direction of the force on the wire.
|dw:1337316891433:dw| Am I right?
I think you are right let me double check
IL X B so it is ILB Sin(theta) so yes :)
Vat abt the direction? :)
I think it will point into the screen let me check tho
force will always be perpendicular to the plane containing the direction of magnetic field and the wire.
but either way it will be perpendicular to both the Length of the wire and B
|dw:1337272230240:dw| I think this is how it will look. At least in my mind.
In that pic the force points away from screen.
use right hand rule|dw:1337272446404:dw| think of your knuckles as L and tip of fingers as B and F is where your thumb points too. Sorry about drawing :P
V need to use right hand rule or fleming's left hand rule? I remember that in the right hand rule the thumb points towards the direction of the current. Am I right? am nt sure?
these are all derivative of vector multiplication ...
qVxB|dw:1337272984176:dw|
qVxB the first term always curls into the second term Then use right hand rule Knuckles is first term, tip of fingers is second term and thumb is the product (force)
oh k. In both ways of u guys @timo86m and @experimentX and in my way the answer comes as the same
Well you have to use your formula either way Sin(theta) *ILB but you need IL x B to know that L curls into B :)
Thanxxxx for the help.:)