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 2 years ago
Plzzz help.
the following figure shows a long wire carrying a current of 30A. The rectangular loop carries a current of 20A. Calculate the resultant force acting on the loop. Assume that a=1cm, b=8cm and l=30cm.
 2 years ago
Plzzz help. the following figure shows a long wire carrying a current of 30A. The rectangular loop carries a current of 20A. Calculate the resultant force acting on the loop. Assume that a=1cm, b=8cm and l=30cm.

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ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1337319857835:dw

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0u mean my answer for B?

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.1I think it will involve integration.

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1337320632924:dw This is to find the force on the second current conductor.

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry so bad at drawing. :(

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.1ah ok i think i found it in book i wil lattach 2 files hold on

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0Ya. it helps a lot. Bt y hav they given the value of l. It is askd to find the resultant force.

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.1i is amps. Is that what you mean?

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0No. In ur attachment the question is to fin the magnetic force on the top of the wire b. And in the equation given in the solution there is no l bt only a nd b r there. in my question the value of l is also given. I am wondering y that was given and the magnetic force askd to b found here is the resultant.

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0i mean top of the wire of length b.

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.1Not sure just solve for whatever variable or convert. :) but the diagram is almost exactly the same :)

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0ha k. thannnnxxxxxxxx a lot.

ujjwal
 2 years ago
Best ResponseYou've already chosen the best response.1Is your answer equal to 0.0032 N ?

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0i get a different answer. Bt can u pls show me hw u got ur answer if u dnt mind?

ujjwal
 2 years ago
Best ResponseYou've already chosen the best response.1sure, the dw:1337350437168:dw there exists an attractive force F1 and a repulsive force F2 between the wires carrying 30 amp and 20 amp.. Calculate both forces and find their difference.. that's all..

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0which formula did u use here to find it?

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0i got the answer as 0.00315N.

ujjwal
 2 years ago
Best ResponseYou've already chosen the best response.1It involves large numbers.. your answer seems to be correct.. I used the relation\[F=mu _{0}I _{1} I _{2}l/2pi r \]

ujjwal
 2 years ago
Best ResponseYou've already chosen the best response.1what's wrong with OS? but i guess you got the relation i used...

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0ya. do u knw how to derive this relation from this dw:1337397048799:dw

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1337397220582:dw

ujjwal
 2 years ago
Best ResponseYou've already chosen the best response.1I guess i can't see the whole relation.. I can't see it at rightmost part.. Is there a lower limit?? It's a line integral in closed path , isn't it? why do you need limits?? I can't see the whole relation though..

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1337397679038:dw

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1337397784654:dw This formula is to find the force on the second conductor. Can u @Shivam_bhalla explain hw it becomes dw:1337397890531:dw. Plzzzz.

shivam_bhalla
 2 years ago
Best ResponseYou've already chosen the best response.0@ajprincess , Take a look here >http://cnx.org/content/m31103/latest/

shivam_bhalla
 2 years ago
Best ResponseYou've already chosen the best response.0The above link for magnetic field due to a wire and its derivation. Now I will explain that concept which you want me to do so.

shivam_bhalla
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1337353084406:dw Consider 2 parallel wires carrying current I_1 and I_2 Force exerted by wire 1 on wire 2 is F= (B_1) (I_2)(distance between two wires)

shivam_bhalla
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry I wrote that in a hurry. It should be F= (B_1) (I_2)(length of wire 2) Now as in the previous link I gave to you, we see that \[B_1 = \frac { \mu_0 I_1 }{2 \pi r}\] \[F=B_1I_2(length \space of \space wire \space 2)\] \[\frac{F}{length \space of \space wire \space 2} = \frac { \mu_0 I_1 }{2 \pi r} I_2\] \[f=\frac { \mu_0 I_1I_2}{2 \pi r} \] where\[ f = \frac{F}{length \space of \space wire \space 2}\]

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0Thanxxxx a lot @Shivam_bhalla

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0Thanxx a lot @ujjwal
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